Calculate the mass of sodium acetate (CH3COONa) required to Chapter 1: Some Basic Concepts of Chemistry Chemistry Class 11 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 5: Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-1 is solved by our expert teachers. You can get ncert solutions and notes for class 11 chapter 1 absolutely free. NCERT Solutions for class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry is very essencial for getting good marks in CBSE Board examinations
Answer
Given that
0.375 Molar aqueous solution
Molar represent molarity of the solution
Hence given molarity of solution will 0.375M
Formula of molarity
Molarity (M) = No. of moles of solute / volume of solution in liter
Volume in liter = 500 ml = 0.5 liter (1000 ml = 1 liter)
Plug the values in above formula we get
Number of moles = 0.375 × 0.5 = 0.1875 mol
Use formula
Number of moles = mass / molar mass
Molar mass of sodium acetate = 82.0245 g mole-1 (Given)
Plug above values in formula we get
Mass of sodium acetate = (82.0245 g mol-1) (0.1875 mole) = 15.38 g
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