Home UP BOARD Question Papers NCERT Solutions Sample Papers CBSE Notes NCERT Books CBSE Syllabus

In Three Moles of Ethane C2h6 Calculate Following Number of Moles Exercise Chapter 1 Some Basic Concepts of Chemistry

In three moles of ethane (C2H6) calculate the following Chapter 1: Some Basic Concepts of Chemistry Chemistry Class 11 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 10: In three moles of ethane (C2H6), calculate the following: (i) Number of moles of carbon atoms. (ii) Number of moles of hydrogen atoms. (iii) Number of molecules of ethane. is solved by our expert teachers. You can get ncert solutions and notes for class 11 chapter 1 absolutely free. NCERT Solutions for class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry is very essencial for getting good marks in CBSE Board examinations

Language of Video is English or Hindi

Answer

(i) There are two atoms of Carbon in each C2H6 molecules hence 1 mole of C2H6 will have 2 moles of carbon atoms. So that Number of moles of carbon atoms in 3 moles of C2H6 = 2 × 3 = 6 moles

(ii) There are six atoms of hydrogen in each molecules of C2H6 hence 1 mole of C2H6 will have 6 moles of hydrogen atoms. So that Number of moles of carbon atoms in 3 moles of C2H6 = 3 × 6 = 18 moles

(iii) Each mole of any substance has 6.023 × 1023 particles so that 3 mol of C2H6
will have = 3 × 6.023 × 1023 = 18.069 × 1023 molecules.

Important Links

NCERT CBSE Notes Class 6 - 12 Download pdf

Ncert Solution for class 6 to 12 download in pdf

CBSE Model test papars Download in pdf

NCERT Books for Class 1- 12 Hindi & English Medium

Mathematics Biology Psychology
Chemistry English Economics
Sociology Hindi Business Studies
Geography Science Political Science
Statistics Physics Accountancy

CBSE Syllabus Class 9 to 12 Year 2021-22

Last year CBSE Question paper

Important Links

Follow Us On

Face book page ncerthelp twitter page youtube page linkdin page

Solved Last Year Question Paper

If You have any problem/query related to above page please send us your Query to ncerthelp@gmail.com with code Serial No1321/108. Thanks

Please Share this webpage on facebook, whatsapp, linkdin and twitter.

Facebook Twitter whatsapp Linkdin

Copyright @ ncerthelp.com A free educational website for CBSE, ICSE and UP board.