Calculate the mass percent of different elements present in sodium sulphate Chapter 1: Some Basic Concepts of Chemistry Chemistry Class 11 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 2: Calculate the mass percent of different elements present in sodium sulphate (Na2SO4) is solved by our expert teachers. You can get ncert solutions and notes for class 11 chapter 1 absolutely free. NCERT Solutions for class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry is very essencial for getting good marks in CBSE Board examinations
Answer
$$Mass;\% ;of;an;element; = ;{{molar;mass;of;component} over {molar;mass;of;compound}}; imes ;100$$
The molecular formula of compound (Na2SO4).is
Use Appendix II of NCERT book at page 232
= [(2 × 22.99) + (32.06) + 4 (16.00)]
= 142.04 g
Molar mass of 2Na = 2 × 22.99 = 45.98 amu
Molar mass of 4O = 4 × 16.00 = 64.00 amu
Plug the values in above formula
Mass percent of sodium: = 45.98 ×100 /142.04 = 32.37%
Mass percent of sulphur: = 32.06 ×100 /142.04 = 22.57%
Mass percent of oxygen: = 64.00 ×100 /142.04 = 45.06%
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