Calculate the concentration of nitric acid in moles per litre Chapter 1: Some Basic Concepts of Chemistry Chemistry Class 11 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 6: Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL-1 and the mass per cent of nitric acid in it being 69%. is solved by our expert teachers. You can get ncert solutions and notes for class 11 chapter 1 absolutely free. NCERT Solutions for class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry is very essencial for getting good marks in CBSE Board examinations
Answer
Given that Mass percent of nitric acid in the sample = 69 %
When mass % is given always take total mass = 100 g
Mass of nitric acid = 69% of 100 g = 69 g
Molar mass of nitric acid (HNO3)
= {1 + 14 + 3(16)} g mol-1 = 1 + 14 + 48 = 63 g mol-1
Use formula density = mass / volume
Given that density = 1.41 g ml-1
Total mass = 100 g
Plug the values in above formula
Volume of nitric acid = 100/1.41 = 70.92 ml
Concentration in moles per litre = number of moles / volume in liter …(1)
Number of moles = mass / molar mass …(2)
Molar mass of nitric acid (HNO3) = 1×1 + 14 + 3 × 16 = 63 amu
Plug the value in equation (2) we get
Number of moles of HNO3 = 69/63 = 1.095
Volume in liter = 70.92 ml = 0.07092 liter (divide by 1000 to convert in liter)
Plug the value in equation (1), we get
Concentration in moles per liter = 1.095/ 0.07092 = 15.44 mol / liter
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