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(iii) In this part mass of two reactants are given so we need to find the limiting reagent first
Atomic mass of C = 12 amu
Molecular mass of O2 = 2 × 16.00 = 32 amu
2 mol of C = 2 x 12 = 24 g
According to Stoichiometry of the reaction
12 g C will react with = 32 g of O2
1 g of C will react with = 32/ 12 g O2
24 g of C will react with = 24 × 32 / 12 = 64 g O2
But we have only 16 g O2
Given mass of O2 (16 g) < required mass of O2 (64g)
Hence O2 is limiting reagent and product is always calculated with the help of mass of limiting reagent
Molecular mass of CO2 = 12 + 2× 16 = 44 amu
From the reaction
32 g of O2 produce = 44 g CO2
1 g of O2 Produce = 44/32 g CO2
16 g O2 will produce = 44 × 16 / 32 = 22 g CO2
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