ncert solution for class 11 chapter 1 some basic concepts of chemistry Chapter 1: Some Basic Concepts of Chemistry Chemistry Class 11 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 4 part 2: Calculate the amount of carbon dioxide that could be produced when 1 mole of carbon is burnt in 16 g of dioxygen. is solved by our expert teachers. You can get ncert solutions and notes for class 11 chapter 1 absolutely free. NCERT Solutions for class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry is very essencial for getting good marks in CBSE Board examinations
(ii) In this part mass of two reactants are given so we need to find the limiting reagent first
Atomic mass of C = 12 amu
Molecular mass of O2 = 2 × 16.00 = 32 amu
According to Stoichiometry of the reaction
12 g C will react with 32 g of O2
But we have only 16 g O2
Given mass of O2 (16 g) < required mass of O2 (32g)
Hence O2 is limiting reagent and product is always calculated with the help of mass of limiting reagent
Molecular mass of CO2 = 12 + 2× 16 = 44 amu
From the reaction
32 g of O2 produce = 44 g CO2
1 g of O2 Produce = 44/32 g CO2
16 g O2 will produce = 44 × 16 / 32 = 22 g CO2
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