Determine the empirical formula of an oxide of iron which has Chapter 1: Some Basic Concepts of Chemistry Chemistry Class 11 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 3: Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass. is solved by our expert teachers. You can get ncert solutions and notes for class 11 chapter 1 absolutely free. NCERT Solutions for class 11 Chemistry Chapter 1: Some Basic Concepts of Chemistry is very essencial for getting good marks in CBSE Board examinations
Answer
Mass % of iron = 69.9 % [Given]
Mass % of oxygen = 30.1 % [Given]
|
Element |
Atomic mass |
Mass % |
Mass % / atomic mass |
|
Fe |
55.85 |
69.9 |
69.9/55.85 = 1.25 |
|
O |
16.00 |
30.1 |
30.1/16.00 = 1.88 |
Fe : O = 1.25 : 1.88
Convert in simple ratio we get
Fe : O = 2 : 3
Hence, the empirical formula of the iron oxide is Fe2O3.
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