CBSE Class 4 Mathematics NCERT Solutions: Unit 6 - The Junk Seller
This unit, 'The Junk Seller,' for CBSE Class 4 Mathematics, introduces practical applications of arithmetic in everyday scenarios. Students will explore concepts related to calculating earnings from daily work, understanding the basics of loans and repayment, and determining the cost of goods like newspapers based on weight. The exercises involve multiplication and subtraction to solve real-world problems, such as calculating daily and monthly income from a tea stall or rickshaw rentals, and figuring out the total cost of junk. These solutions provide step-by-step guidance, making it easier for students to grasp these financial concepts and improve their problem-solving skills for exams.
Quick info
| Board | CBSE |
|---|---|
| Class | Class 4 |
| Subject | Mathematics |
| Session | 2026 |
| Language | English |
| Type | NCERT Solutions |
| Chapter | Unit-6 The Junk Seller |
Chapter summary
Unit 6, 'The Junk Seller,' focuses on applying basic arithmetic operations to real-life financial situations. It covers calculating earnings from services like tea stalls and rickshaw rentals, understanding the concept of loans and how they are repaid with interest, and calculating the cost of materials like newspapers based on quantity. The exercises are designed to build computational fluency and logical reasoning in young learners.
Learning outcomes
- Understand basic concepts of earning and profit.
- Calculate daily and monthly earnings from simple jobs.
- Learn about loans and the process of repayment.
- Solve problems involving multiplication to find costs and earnings.
- Apply subtraction to find missing values in financial calculations.
- Relate mathematical concepts to real-world financial scenarios.
Topics covered
Paper topics
- Calculating daily earnings
- Calculating monthly earnings
- Understanding loans
- Loan repayment calculations
- Cost calculation based on weight
- Multiplication for earnings
- Subtraction for missing values
- Real-world financial math
Important topics
- Calculating earnings from multiple sources
- Understanding loan principal and repayment
- Multiplication for cost and earnings
- Applying math to everyday financial situations
PDF preview
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Questions and Solutions
Question 1
This is a personal question. Some students might find Maths challenging, while others may not. The key to finding Maths easy is regular practice and understanding the concepts thoroughly. Consistent effort can make even difficult topics manageable.
Question 2
Similar to the previous question, the perception of difficulty varies among students. Many find that with regular practice and clear explanations, no topic in the Maths book is inherently difficult. Understanding the underlying principles makes all lessons seem manageable.
Question 3
The easiest lesson is subjective and depends on individual understanding and practice. For many students, lessons that involve simple arithmetic operations and have clear, relatable examples might seem the easiest. However, consistent practice is crucial for mastering any lesson.
Question 4
To find the cost of a cup of tea at a tea stall, you would typically ask the vendor or observe the price list. Based on common knowledge, the price can vary, but a typical cost at a local tea stall is often around Rs 3 to Rs 5.
Answer: At a tea stall, a cup of tea usually costs Rs 3.
Question 5
The cost of a cup of tea at a hotel is generally higher than at a tea stall due to the service and ambiance provided. Hotels often charge more for beverages compared to smaller, local establishments.
Answer: At a hotel, a cup of tea typically costs Rs 5.
Question 6
To calculate the total earnings over a period, we multiply the daily earning by the number of days.
Earning in 1 day = Rs 30
Earning in 10 days = Earning per day × Number of days
To calculate the earning in a month, we assume a month has 30 days (a common convention for such problems).
Earning in 30 days = Earning per day × Number of days in a month
Answer: In 10 days, the person will earn Rs 300. In a month (30 days), the person will earn Rs 900.
Question 7
A loan is an amount of money that is borrowed from a person or institution, which needs to be paid back, usually with interest, over a period of time. People often take loans to start a business, buy a house, purchase a vehicle, or for other significant expenses.
Answer: Yes, I have heard of someone taking a loan. He took a loan to start his shop.
Question 8
The question refers to a specific instance mentioned previously or in context. Based on the provided information, the loan amount taken was a specific sum that needs to be repaid.
Answer: He took Rs 10,000 as a loan.
Question 9
The amount paid back includes the original loan amount plus any interest charged. This is the total sum returned to the lender after a certain period.
Answer: He paid back Rs 11,000 after one year.
Question 10
We need to calculate the total amount paid by both Hariya and Babu to compare who paid more.
Hariya's payment: Hariya has to pay Rs 51 every month for six months.
Total paid by Hariya = Monthly payment × Number of months
Babu's payment: Babu has to pay Rs 360.
Comparing the amounts: Rs 306 (Hariya) vs Rs 360 (Babu).
Since Rs 360 is greater than Rs 306, Babu has to pay back more money.
Answer: Babu will have to pay back more money.
Question 11
Kiran earns a certain amount for each rickshaw she rents out. To find her total earnings from multiple rickshaws, we multiply the earning per rickshaw by the number of rickshaws.
Earning from 1 rickshaw = Rs 20
Earning from 9 rickshaws = Earning per rickshaw × Number of rickshaws
This calculation shows that she earns 9 times the amount she earns from one rickshaw.
Answer: Kiran earns Rs 180 from 9 rickshaws in a day.
Question 12
This question uses a slightly different approach to find the earnings for 9 rickshaws, starting from the earnings for 10 rickshaws. If Kiran earns Rs 200 for 10 rickshaws, the earnings for 9 rickshaws would be Rs 200 minus the earning from one rickshaw.
Earning from 10 rickshaws = Rs 200
Earning from 1 rickshaw = Rs 20
Earning from 9 rickshaws = Earning from 10 rickshaws - Earning from 1 rickshaw
Answer: So, for 9 rickshaws, she will get Rs 200 – 20 = 180.
Question 13
To find Kiran's earnings from one rickshaw in a week, we need to multiply her daily earning from one rickshaw by the number of days in a week.
Earning from one rickshaw in 1 day = Rs 20
Number of days in a week = 7
Earning from one rickshaw in 7 days = Earning per day × Number of days
Answer: In a week, Kiran earns Rs 140 from one rickshaw.
Question 14
These are mental math problems involving multiplication. Let's solve each one:
2 × 6 = 12
4 × 80 = 320
20 × 6 = 120
4 × 81 = 324
2 × 60 = 120
9 × 25 = 225
3 × 42 = 126
31 × 9 = 279
Answers:
Question 15
To find the total cost of the newspaper, we need to know the price per kilogram and the total weight of the newspaper. The problem states the cost of 1 kg of newspaper and asks for the cost of 31 kg.
Cost of 1 kg of newspaper = Rs 5
Total weight of newspaper = 31 kg
Total cost = Cost per kg × Total weight
Answer: Kiran will pay Rs 155 for 31 kg of newspaper.
Common mistakes
- Errors in multiplication, especially with larger numbers.
- Misinterpreting the concept of loan repayment (principal + interest).
- Difficulty in applying the correct operation (addition, subtraction, multiplication) to word problems.
- Calculation errors when dealing with multiple steps.
Revision tips
- Practice all multiplication tables thoroughly.
- Read each word problem carefully to identify the core question.
- Break down complex problems into smaller, manageable steps.
- Use the provided solutions to check your work and understand different approaches.
- Try to create similar real-life problems to solve.
Practice MCQs
Q1. If a tea stall owner earns Rs 30 per day, how much will they earn in 10 days?
Explanation: To find the total earnings, multiply the daily earning by the number of days: Rs 30 10 = Rs 300.
Q2. A person took a loan of Rs 10,000 and paid back Rs 11,000. How much extra did they pay?
Explanation: The extra amount paid is the difference between the total paid back and the loan amount: Rs 11,000 - Rs 10,000 = Rs 1,000.
Q3. Kiran earns Rs 20 per rickshaw per day. How much does she earn from 9 rickshaws in a day?
Explanation: Multiply the earning per rickshaw by the number of rickshaws: Rs 20 9 = Rs 180.
Q4. If Kiran earns Rs 20 per day from one rickshaw, how much does she earn in a week (7 days)?
Explanation: Multiply the daily earning by the number of days in a week: Rs 20 7 = Rs 140.
Q5. What is the cost of 31 kg of newspaper if 1 kg costs Rs 5?
Explanation: Multiply the cost per kg by the total kilograms: Rs 5 31 = Rs 155.
Frequently asked questions
What is the main focus of the 'The Junk Seller' unit in Class 4 Maths?
The unit focuses on applying basic arithmetic operations like multiplication and subtraction to real-life financial scenarios, such as calculating earnings from jobs and understanding loan repayments.
How do these NCERT Solutions help students?
These solutions provide clear, step-by-step explanations for each problem, helping students understand the methods used and reinforcing their learning for better exam preparation.
What kind of financial concepts are introduced in this unit?
The unit introduces concepts like daily and monthly earnings from work (tea stall, rickshaws), the idea of taking a loan, and the total amount to be paid back, which includes the principal and any additional charges.
Are there any specific calculation skills practiced in this unit?
Yes, students practice multiplication to calculate earnings and costs, and subtraction to find differences or missing amounts, as seen in problems involving rickshaw earnings and newspaper costs.
How does the unit relate math to everyday life?
It connects mathematical concepts directly to practical situations like running a small business (tea stall, rickshaw rental) and managing personal finances (loans), making math more relevant and engaging.
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