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How Can Three Resistors of Resistances 2 ?, 3 ? and 6 ? Be Connec in Text Question Chapter 12 Electricity Science

In text Q & Answers of page 216 Q-4 How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of (a) 4 Ω, (b) 1 Ω? Chapter 12: Electricity Science Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. How can three resistors of resistances 2 ?, 3 ? and 6 ? be connected to give a total resistance of (a) 4 ?, (b) 1 ?? is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 12 absolutely free. NCERT Solutions for class 10 Science Chapter 12: Electricity is very essencial for getting good marks in CBSE Board examinations

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Ans: There are three resistors of resistances 2 Ω, 3 Ω, and 6 Ω respectively.
(a) If we connect the given three resistors in the following way then we get net resistance as 4Ω
Figure
Here, 6 Ω and 3 Ω resistors are connected in parallel. Therefore, their equivalent resistance will be given by

[egin{align} & ~frac{1}{R}=frac{1}{{{R}_{1}}}+frac{1}{{{R}_{2}}} \ & frac{1}{R}=frac{1}{6}+frac{1}{3} \ & frac{1}{R}=frac{1+2}{6} \ & frac{1}{R}=frac{3}{6}=frac{1}{2} \ end{align}]
⇒R=2 Ω
This equivalent resistor of resistance 2Ω is connected to a 2Ω resistor in series.
Therefore, equivalent resistance of the circuit = 2Ω + 2Ω =4Ω
Hence, the total resistance of the circuit is 4Ω. (b) If we connect the given three resistors in the following way then we get net resistance as 1Ω. Here all the resistors are connected in parallel
Figure
∴ their equivalent resistance will be given as



R=1Ω
Therefore, the net equivalent resistance of the circuit is 1Ω.

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