An electric iron of resistance 20 ? takes a current of 5 A. Calcu

An electric iron of resistance 20 ? takes a current of 5 A. Calculate the heat developed in 30 s. Chapter 12: Electricity Science Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. In text Q & Answers of page 218 Q-3 An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s. is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 12 absolutely free. NCERT Solutions for class 10 Science Chapter 12: Electricity is very essencial for getting good marks in CBSE Board examinations

Language of Video is English or Hindi

Ans: Given that Resistance(R) = 20 Ω, Electric current (I)= 5 A and time(t)= 30 s
Now we know that H= I²Rt
= 5×5×20×30
= 15000J=1.5×104J
∴ The heat developed in 30s is 1.5×104J