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Redraw the Circuit of Q 1, Putting in an Ammeter to Measure the C in Text Question Chapter 12 Electricity Science

In text Q & Answers of page 213 Q-2 Redraw the circuit of Q 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 Ω resistors. What would be the readings in the ammeter and the voltmeter? Chapter 12: Electricity Science Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Redraw the circuit of Q 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 ? resistors. What would be the readings in the ammeter and the voltmeter? is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 12 absolutely free. NCERT Solutions for class 10 Science Chapter 12: Electricity is very essencial for getting good marks in CBSE Board examinations

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Ans: An ammeter should be connected in the circuit in series with the resistors. To measure the potential difference across the resistor it should be connected in parallel, as shown in the following figure.
Circuit Diagram
According to Ohm’s law,
V = IR,
Now Potential difference (V) = 6 V
Let current flowing through the circuit = I
Resistance of the circuit, R = 5 + 8 + 12 = 25 Ω
Since I =V/R
= 6/25
= 0.24 A
Potential difference across 12 Ω resistor = V1
Current flowing through the 12 Ω resistor, I = 0.24 A
Therefore, using Ohm’s law, we obtain
V1 = IR
= 0.24×12=2.88 V
Therefore, the reading of the ammeter will be 0.24 A.
And the reading of the voltmeter will be 2.88 V.

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