CBSE Class 3 Mathematics: Chapter 14 - Rupees and Paise NCERT Solutions

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NCERT Solutions PDF Class 3 PDF

This chapter, 'Rupees and Paise,' for CBSE Class 3 Mathematics, focuses on fundamental money management skills. Students will learn to calculate the cost of multiple items, find the total cost of purchases, and determine the change received after a transaction. The exercises involve simple addition and subtraction of rupees and paise, understanding price lists, and preparing basic cash memos. These NCERT Solutions provide step-by-step guidance to help students grasp these concepts effectively. Practicing these problems will enhance their ability to handle real-life financial situations and prepare them for exams by reinforcing their understanding of currency calculations.

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Quick info

BoardCBSE
ClassClass 3
SubjectMathematics
Session2026
LanguageEnglish
TypeNCERT Solutions
Chapter14. Rupees and Paise

Chapter summary

Chapter 14, 'Rupees and Paise,' for Class 3 Mathematics NCERT Solutions, covers essential money-related arithmetic. It includes exercises on calculating the cost of combined items, finding the total expenditure, and managing money by calculating remaining amounts after purchases. The chapter also touches upon creating simple cash memos and performing addition and subtraction with currency values. These solutions aim to build a strong foundation in practical financial literacy for young learners.

Learning outcomes

  • Understand the relationship between rupees and paise.
  • Calculate the total cost of multiple items.
  • Determine the amount of money left after making a purchase.
  • Perform addition and subtraction with currency values.
  • Prepare a simple cash memo.
  • Solve real-world problems involving money.

Topics covered

Paper topics

  • Introduction to Rupees and Paise
  • Calculating cost of multiple items
  • Finding total cost
  • Money addition
  • Money subtraction
  • Calculating money left
  • Preparing cash memos
  • Understanding price lists

Important topics

  • Calculating total cost of purchases
  • Determining money left after spending
  • Addition and subtraction of rupees and paise
  • Understanding item prices and quantities

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Questions and Solutions

Question A

Without using a pencil or paper, find out the cost of:
  • One ball and one toy car
  • One notebook and two pencils
  • Two bananas and a glass of milk
  • One doll and a ball
  • One glass of lemon juice and a packet of biscuits
Solution:

Here are the costs without needing to write them down, based on the information provided:

  • One ball and one toy car: Rs 22
  • One notebook and two pencils: Rs 10
  • Two bananas and a glass of milk: Rs 6.50
  • One doll and a ball: Rs 15
  • One glass of lemon juice and a packet of biscuits: Rs 7.50

Question B

Find the total cost of:
  • One toy giraffe, one copy and a glass of lemon juice
  • One glass of milk, one packet of biscuits and a banana
  • One notebook, two pencils and two erasers
  • Two tops, three toffees and two bananas
Solution:

Let's calculate the total cost for each set of items:

  1. One toy giraffe, one copy and a glass of lemon juice: Rs 14.50
  2. One glass of milk, one packet of biscuits and a banana: Rs 9.50
  3. One notebook, two pencils and two erasers: Rs 12
  4. Two tops, three toffees and two bananas: Rs 8.50

Question C

What can you buy if you have a twenty rupee note? Choose from the following options:
  • 1 toy car, 1 lemon juice, 1 banana
  • 1 ball, 1 doll, 1 glass milk
  • 1 toy car, 1 packet of biscuits, 1 toffee
  • 1 toy car, 1 toy giraffe, 1 glass milk
Solution:

To determine what can be bought with Rs 20, we need to estimate the cost of each combination. Based on typical prices from the chapter (though not all are explicitly listed for this question, we use context):

  • 1 toy car, 1 lemon juice, 1 banana: A toy car might be around Rs 15, lemon juice Rs 3.50, and a banana Rs 1.50. Total approx Rs 20. This is a possible purchase.
  • 1 ball, 1 doll, 1 glass milk: A ball (Rs 7), a doll (Rs 8), and milk (Rs 3.50) would total Rs 18.50. This is a possible purchase.
  • 1 toy car, 1 packet of biscuits, 1 toffee: A toy car (Rs 15), biscuits (Rs 4.50), and a toffee (Rs 0.50) would total Rs 20. This is a possible purchase.
  • 1 toy car, 1 toy giraffe, 1 glass milk: A toy car (Rs 15), toy giraffe (Rs 6.50), and milk (Rs 3.50) would total Rs 25. This is more than Rs 20, so it cannot be bought.

Therefore, the first three options are possible purchases with a twenty rupee note.

Question D

Monu prepared the following cash memos. Check the cash memos and correct them if you find a mistake. The correct memos are given as follows:

Cash Memo 1: Self Service Store. Item: 1 ball, Rate: Rs 7.00. Item: 3 pencils, Rate: Rs 2.50. Item: 5 toffees, Rate: Rs 0.50. Total should be calculated.

Cash Memo 2: Self Service Store. Item: 1 toy car, Rate: Rs 15.00. Item: 3 glasses milk, Rate: Rs 3.50 per glass. Item: 4 notebooks, Rate: Rs 5.00 per notebook. Total should be calculated.

Cash Memo 3: Self Service Store. Item: 1 toy car, Rate: Rs 15.00. Item: 3 pencils, Rate: Rs 2.50. Item: 7 toffees, Rate: Rs 0.50. Item: 1 biscuit, Rate: Rs 4.50. Total should be calculated.

Solution:

Let's check and correct each cash memo:

Corrected Cash Memo 1:

Self Service Store

Item Rate per item (₹) Paise Total Cost (₹)
1 ball 7 00 7.00
3 pencils 2.50 (7.50) 7.50
5 toffees 0.50 (2.50) 2.50
TOTAL 17.00

Explanation: 3 pencils at Rs 2.50 each cost 3 * 2.50 = Rs 7.50. 5 toffees at Rs 0.50 each cost 5 * 0.50 = Rs 2.50. Total = 7.00 + 7.50 + 2.50 = Rs 17.00.

Corrected Cash Memo 2:

Self Service Store

Item Rate per item (₹) Paise Total Cost (₹)
1 toy car 15 00 15.00
3 glasses milk 3.50 (10.50) 10.50
4 notebooks 5 00 20.00
TOTAL 45.50

Explanation: 3 glasses of milk at Rs 3.50 each cost 3 * 3.50 = Rs 10.50. 4 notebooks at Rs 5.00 each cost 4 * 5.00 = Rs 20.00. Total = 15.00 + 10.50 + 20.00 = Rs 45.50.

Corrected Cash Memo 3:

Self Service Store

Item Rate per item (₹) Paise Total Cost (₹)
1 toy car 15 00 15.00
3 pencils 2.50 (7.50) 7.50
7 toffees 0.50 (3.50) 3.50
1 biscuit 4.50 (4.50) 4.50
TOTAL 30.50

Explanation: 3 pencils at Rs 2.50 each cost 3 * 2.50 = Rs 7.50. 7 toffees at Rs 0.50 each cost 7 * 0.50 = Rs 3.50. 1 biscuit costs Rs 4.50. Total = 15.00 + 7.50 + 3.50 + 4.50 = Rs 30.50.

Question (Add the following)

Add the following amounts:
  1. Rs 12.50 and Rs 13.00
  2. Rs 55.50 and Rs 14.00
  3. Rs 30.00 and Rs 31.50
Solution:

Let's perform the addition for each pair of amounts:

  1. Rs 12.50 + Rs 13.00 = Rs 25.50
  2. Rs 55.50 + Rs 14.00 = Rs 69.50
  3. Rs 30.00 + Rs 31.50 = Rs 61.50

Question (Subtract the following)

Subtract the following amounts:
  1. Rs 25.50 from Rs 11.50
  2. Rs 103.50 from Rs 62.00
  3. Rs 19.50 from Rs 7.00
Solution:

Let's perform the subtraction for each pair of amounts:

  1. Rs 11.50 - Rs 25.50 = -Rs 14.00 (This indicates that Rs 11.50 is less than Rs 25.50. If the question implies finding the difference, it would be Rs 14.00. If it implies a transaction where you owe money, the result is negative.)
  2. Rs 62.00 - Rs 103.50 = -Rs 41.50 (Similar to the above, Rs 62.00 is less than Rs 103.50.)
  3. Rs 7.00 - Rs 19.50 = -Rs 12.50 (Rs 7.00 is less than Rs 19.50.)

Note: The subtractions as written result in negative numbers, implying the first amount is smaller than the second. If the intention was to subtract the smaller from the larger, the results would be positive differences.

Question E (Part 1)

If you have 30 rupees with you, find out how much money will be left after buying the following items: One ball, one doll and one toy giraffe.
Solution:

First, we find the total cost of the items purchased:

  • Price of one ball = Rs 7.00
  • Price of one doll = Rs 8.00
  • Price of one toy giraffe = Rs 6.50

Total cost = Rs 7.00 + Rs 8.00 + Rs 6.50 = Rs 21.50

Now, we calculate the money left:

Money left = Total money - Money spent

Money left = Rs 30.00 - Rs 21.50 = Rs 8.50

Answer: Rs 8.50 will be left.

Question E (Part 2)

If you have 30 rupees with you, find out how much money will be left after buying the following items: Two bananas, one pack of biscuits and two glasses of lemon juice.
Solution:

First, let's calculate the cost of all the items:

  • Price of 1 banana = Rs 1.50
  • So, the price of 2 bananas = 1.50 \times 2 = \text{Rs } 3.00
  • Price of one pack of biscuits = Rs 4.50
  • Price of one glass of lemon juice = Rs 3.00
  • So, the price of two glasses of lemon juice = 3.00 \times 2 = \text{Rs } 6.00

Total cost = Rs 3.00 (bananas) + Rs 4.50 (biscuits) + Rs 6.00 (lemon juice) = Rs 13.50

Now, calculate the money left:

Money left = Total money - Money spent

Money left = Rs 30.00 - Rs 13.50 = Rs 16.50

Answer: Rs 16.50 will be left.

Question E (Part 3)

If you have 30 rupees with you, find out how much money will be left after buying the following items: Three notebooks, two pencils and two erasers.
Solution:

To find the money left, we first need to calculate the total cost of the items:

  • Price of 1 notebook = Rs 5.00
  • So, the price of 3 notebooks = 5.00 \times 3 = \text{Rs } 15.00
  • Price of 1 pencil = Rs 2.50
  • So, the price of 2 pencils = 2.50 \times 2 = \text{Rs } 5.00
  • Price of 1 eraser = Rs 2.00 (Assuming from context, as not explicitly given for this part but implied by total in a similar question)
  • So, the price of 2 erasers = 2.00 \times 2 = \text{Rs } 4.00

Total cost = Rs 15.00 (notebooks) + Rs 5.00 (pencils) + Rs 4.00 (erasers) = Rs 24.00

Now, we calculate the money left:

Money left = Total money - Money spent

Money left = Rs 30.00 - Rs 24.00 = Rs 6.00

Answer: Rs 6.00 will be left.

Common mistakes

  • Errors in decimal placement when adding or subtracting rupees and paise.
  • Incorrectly calculating the cost of multiple identical items (e.g., 2 bananas).
  • Forgetting to carry over or borrow when adding/subtracting paise.
  • Misinterpreting the quantities of items listed in a purchase.

Revision tips

  • Practice converting between rupees and paise to build number sense.
  • Work through each cash memo problem carefully, checking your addition.
  • Use real coins and notes (or play money) to visualize the transactions.
  • Focus on understanding the 'money left' calculation as it involves subtraction.
  • Review the price lists and item quantities before calculating totals.

Practice MCQs

Q1. What is the total cost of one ball and one toy car?

Q2. If one banana costs Rs 1.50, what is the cost of two bananas?

Q3. What is the total cost of one toy giraffe, one copy, and one glass of lemon juice?

Q4. If Monu spent Rs 21.50 on one ball, one doll, and one toy giraffe, and had Rs 30.00 initially, how much money is left?

Q5. How much is 7 rupees and 50 paise plus 5 rupees and 50 paise?

Frequently asked questions

What is the main focus of the 'Rupees and Paise' chapter for Class 3 Maths?

The chapter focuses on practical money management skills, including calculating costs, totals, and remaining money, using addition and subtraction with rupees and paise.

How do these NCERT Solutions help students?

These solutions provide clear, step-by-step explanations for each problem, helping students understand the methods for solving money-related questions and build confidence.

What kind of calculations are involved in this chapter?

The chapter involves basic arithmetic operations like addition and subtraction applied to monetary values (rupees and paise).

Are there any exercises on making cash memos?

Yes, the chapter includes exercises where students learn to prepare simple cash memos and check existing ones for errors.

How can I use these solutions for exam preparation?

You can use these solutions to practice solving various types of money problems, understand the correct methods, and check your answers to reinforce your learning.

Important links

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