CBSE Class 7 Mathematics Chapter 8: Comparing Quantities NCERT Solutions
This chapter, Comparing Quantities, is a fundamental part of the Class 7 Mathematics curriculum. It introduces students to the concept of comparing different quantities using ratios and percentages. The NCERT Solutions for Chapter 8 are designed to help students understand how to express relationships between quantities, convert between different units for comparison, and solve real-world problems involving these concepts. Key topics covered include finding ratios, understanding and calculating percentages, and applying these to problems like profit and loss. These solutions provide step-by-step guidance, making complex calculations accessible and reinforcing learning. They are an excellent resource for students to practice and prepare for their examinations, ensuring a strong grasp of quantitative comparison techniques.
Quick info
| Board | CBSE |
|---|---|
| Class | Class 7 |
| Subject | Mathematics |
| Session | 2026 |
| Language | English |
| Type | NCERT Solutions |
| Chapter | Chapter 8: Comparing Quantities |
Chapter summary
Chapter 8 of the NCERT Class 7 Mathematics textbook focuses on Comparing Quantities. The exercises cover finding ratios between different units, calculating the number of items needed based on given ratios, and determining population density. Students learn to convert units to ensure consistent comparison and apply ratio concepts to practical scenarios. These solutions break down each problem, offering clear methods to calculate ratios and understand population distribution, aiding students in mastering quantitative comparisons.
Learning outcomes
- Understand the concept of ratio and its application.
- Convert quantities to the same unit for accurate ratio calculation.
- Solve problems involving ratios and proportions.
- Calculate population density and compare population distribution.
- Apply ratio concepts to real-world scenarios.
Topics covered
Paper topics
- Ratio
- Comparison of Quantities
- Unit Conversion for Ratios
- Percentage
- Profit and Loss (implied by comparison concepts)
- Population Density
- Problem Solving with Ratios
Important topics
- Calculating Ratios
- Unit Conversion for Comparison
- Population Density Calculation
- Applying Ratios to Real-World Problems
PDF preview
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Questions and Solutions
Question 1
- ₹5 to 50 paise
- 15 kg to 210 g
- 9 m to 27 cm
- 30 days to 36 hours
To calculate a ratio between two quantities, it is essential that both quantities are expressed in the same unit. We will convert them to the smaller unit where applicable.
- Ratio of ₹5 to 50 paise: First, convert ₹5 into paise. Since ₹1 = 100 paise, ₹5 = 5 \times 100 paise = 500 paise. Now, the ratio is 500 paise to 50 paise. The ratio can be written as a fraction: . Simplifying this fraction, we get . Therefore, the ratio is 10:1.
- Ratio of 15 kg to 210 g: Convert 15 kg into grams. Since 1 kg = 1000 g, 15 kg = 15 \times 1000 g = 15000 g. Now, the ratio is 15000 g to 210 g. The ratio as a fraction is . To simplify, we can divide both numerator and denominator by 10: . Both numbers are divisible by 3: . Therefore, the ratio is 500:7.
- Ratio of 9 m to 27 cm: Convert 9 meters into centimeters. Since 1 m = 100 cm, 9 m = 9 \times 100 cm = 900 cm. Now, the ratio is 900 cm to 27 cm. The ratio as a fraction is . Both numbers are divisible by 9: . Therefore, the ratio is 100:3.
- Ratio of 30 days to 36 hours: Convert 30 days into hours. Since 1 day = 24 hours, 30 days = 30 \times 24 hours = 720 hours. Now, the ratio is 720 hours to 36 hours. The ratio as a fraction is . We know that 720 is 20 times 36 (since 72 / 36 = 2). So, . Therefore, the ratio is 20:1.
Question 2
We are given that 6 students require 3 computers. We need to find out how many computers are needed for 24 students.
First, let's find out how many computers are needed for 1 student. If 6 students need 3 computers, then 1 student needs computers.
Simplifying this, 1 student needs (or 0.5) computers.
Now, to find the number of computers needed for 24 students, we multiply the number of computers per student by 24:
Number of computers =
Number of computers = 12
Thus, 12 computers will be needed for 24 students.
Question 3
- How many people are there per km<sup>2</sup> in both states?
- Which state is less populated?
To determine how many people are there per square kilometer (population density), we need to divide the total population of a state by its total area.
- Population density in Rajasthan and U.P.: The formula for population density is: Population Density = . For Rajasthan: Population = 570 lakh Area = 3 lakh km<sup>2</sup> Population Density of Rajasthan = = 190 people per km<sup>2</sup>. For U.P.: Population = 1660 lakh Area = 2 lakh km<sup>2</sup> Population Density of U.P. = = 830 people per km<sup>2</sup>. So, Rajasthan has 190 people per km<sup>2</sup>, and U.P. has 830 people per km<sup>2</sup>.
- Which state is less populated? Comparing the population densities calculated above: Rajasthan: 190 people per km<sup>2</sup> U.P.: 830 people per km<sup>2</sup> Since 190 is less than 830, Rajasthan has a lower population density. Therefore, Rajasthan is less populated in terms of people per square kilometer.
Common mistakes
- Not converting quantities to the same unit before calculating the ratio.
- Errors in simplifying fractions when calculating ratios.
- Misinterpreting the relationship between quantities in proportion problems.
- Calculation errors when converting units (e.g., days to hours, kg to g).
Revision tips
- Always ensure units are the same before calculating any ratio.
- Practice converting between different units (e.g., ₹ to paise, kg to g, m to cm, days to hours).
- Pay close attention to the wording of problems to correctly identify what is being compared.
- Review the steps for calculating population density and understand its meaning.
Practice MCQs
Q1. What is the ratio of ₹5 to 50 paise?
Explanation: First, convert ₹5 to paise: ₹5 = 5 * 100 paise = 500 paise. The ratio is 500 paise: 50 paise, which simplifies to 10:1.
Q2. If 3 computers are for every 6 students, how many computers are needed for 24 students?
Explanation: The ratio of students to computers is 6:3, or 2:1. For 24 students, you would need half that number of computers, which is 12.
Q3. What is the ratio of 9 meters to 27 centimeters?
Explanation: Convert 9 meters to centimeters: 9 m = 9 * 100 cm = 900 cm. The ratio is 900 cm: 27 cm, which simplifies to 100:3.
Q4. Population density is calculated as:
Explanation: Population density represents the number of people per unit area, hence it is calculated by dividing the total population by the total area.
Q5. Which unit conversion is NOT required in Exercise 8.1, Question 1?
Explanation: The question involves ratios of money, mass, and length, requiring conversions between rupees/paise, kg/g, and m/cm. Liters to milliliters is not part of this question.
Frequently asked questions
What is the main concept covered in CBSE Class 7 Maths Chapter 8?
Chapter 8, Comparing Quantities, focuses on understanding and using ratios and percentages to compare different values and solve real-world problems.
Why is it important to convert units before finding a ratio?
To find a meaningful ratio, both quantities must be in the same unit. For example, you cannot directly compare rupees with paise or kilograms with grams without conversion.
How do these NCERT Solutions help students?
These solutions provide clear, step-by-step explanations for each problem, helping students understand the methods and calculations involved in comparing quantities, which aids in exam preparation.
What kind of problems are included in Exercise 8.1?
Exercise 8.1 includes problems on finding ratios between different units (like money, mass, length, time) and applying ratios to find unknown quantities or compare populations.
What is population density and how is it calculated?
Population density is the number of people living per unit area. It is calculated by dividing the total population of a region by its total area.
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