CBSE Class 7 Mathematics Chapter 4: Simple Equations NCERT Solutions

Reviewed by NCERT Help Editorial Team · Updated on 29 Jul 2026

NCERT Solutions PDF Class 7 PDF

CBSE Class 7 Mathematics Chapter 4: Simple Equations introduces the basics of algebraic equations. This chapter explains what an equation is, the concept of a solution, and how to verify if a particular number satisfies an equation. Students will learn to check given values in different linear equations and complete tables to confirm solutions. The NCERT Solutions offer detailed, step-by-step guidance to help students grasp these fundamental concepts. Mastering simple equations is essential for building a strong foundation in algebra and problem-solving skills, which are vital for advanced mathematical learning. These solutions aim to provide clarity and build confidence for students preparing for their exams.

Home

Quick info

Board	CBSE
Class	Class 7
Subject	Mathematics
Session	2026
Language	English
Type	NCERT Solutions
Chapter	Chapter 4: Simple Equations

Chapter summary

Chapter 4, Simple Equations, for Class 7 Mathematics focuses on understanding the basic structure of equations and verifying solutions. The NCERT Solutions cover exercises that require students to complete tables by testing different values in equations and to check if specific given values are indeed solutions to the provided equations. This chapter lays the groundwork for more complex algebraic concepts by emphasizing the trial-and-error method and substitution.

Learning outcomes

Understand the concept of a simple equation.
Verify if a given value is a solution to an equation.
Complete tables by testing values in equations.
Identify the Left Hand Side (LHS) and Right Hand Side (RHS) of an equation.
Apply substitution to check solutions.

Topics covered

Paper topics

Introduction to Simple Equations
Understanding Solutions
Verifying Solutions by Substitution
Completing Tables for Equations
Left Hand Side (LHS)
Right Hand Side (RHS)
Linear Equations in One Variable

Important topics

Verifying solutions by substitution
Understanding the concept of satisfying an equation
LHS vs RHS comparison
Solving simple linear equations

PDF preview

Read page by page below. PDF is streamed from the official NCERT website — no download button on this page.

Loading document …

Page of

Loading page …

Questions and Solutions

Question 1

Complete the last column of the table:

No. Equation Value Say, whether the Equation is satisfied. (Yes / No)
$x + 3 = 0$ $x = 3$
$x + 3 = 0$ $x = 0$
$x + 3 = 0$ $x = -3$
$x - 7 = 1$ $x = 7$
$x - 7 = 1$ $x = 8$
$5x = 25$ $x = 0$
$5x = 25$ $x = 5$
$5x = 25$ $x = -5$
$\frac{m}{3} = 2$ $m = -6$
$\frac{m}{3} = 2$ $m = 0$
$\frac{m}{3} = 2$ $m = 6$

Solution:

To complete the table, we substitute the given value of the variable into the equation and check if the Left Hand Side (LHS) equals the Right Hand Side (RHS).

For the equation $x + 3 = 0$ and value $x = 3$ :
LHS = $3 + 3$ = $6$

RHS = $0$

Since $6 \neq 0$ , the equation is not satisfied. No.
For the equation $x + 3 = 0$ and value $x = 0$ :
LHS = $0 + 3$ = $3$

RHS = $0$

Since $3 \neq 0$ , the equation is not satisfied. No.
For the equation $x + 3 = 0$ and value $x = -3$ :
LHS = $-3 + 3$ = $0$

RHS = $0$

Since $0 = 0$ , the equation is satisfied. Yes.
For the equation $x - 7 = 1$ and value $x = 7$ :
LHS = $7 - 7$ = $0$

RHS = $1$

Since $0 \neq 1$ , the equation is not satisfied. No.
For the equation $x - 7 = 1$ and value $x = 8$ :
LHS = $8 - 7$ = $1$

RHS = $1$

Since $1 = 1$ , the equation is satisfied. Yes.
For the equation $5x = 25$ and value $x = 0$ :
LHS = $5 \times 0$ = $0$

RHS = $25$

Since $0 \neq 25$ , the equation is not satisfied. No.
For the equation $5x = 25$ and value $x = 5$ :
LHS = $5 \times 5$ = $25$

RHS = $25$

Since $25 = 25$ , the equation is satisfied. Yes.
For the equation $5x = 25$ and value $x = -5$ :
LHS = $5 \times (-5)$ = $-25$

RHS = $25$

Since $-25 \neq 25$ , the equation is not satisfied. No.
For the equation $\frac{m}{3} = 2$ and value $m = -6$ :
LHS = $\frac{-6}{3}$ = $-2$

RHS = $2$

Since $-2 \neq 2$ , the equation is not satisfied. No.
For the equation $\frac{m}{3} = 2$ and value $m = 0$ :
LHS = $\frac{0}{3}$ = $0$

RHS = $2$

Since $0 \neq 2$ , the equation is not satisfied. No.
For the equation $\frac{m}{3} = 2$ and value $m = 6$ :
LHS = $\frac{6}{3}$ = $2$

RHS = $2$

Since $2 = 2$ , the equation is satisfied. Yes.

Question 2

Check whether the value given in the brackets is a solution to the given equation or not:

$n+5=19$ ( $n=1$ )
$7n+5=19$ ( $n=-2$ )
$7n+5=19$ ( $n=2$ )
$4p-3=13$ ( $p=1$ )
$4p-3=13$ ( $p=-4$ )
$4p-3=13$ ( $p=0$ )

Solution:

To check if the given value is a solution, we substitute the value into the equation and see if the LHS equals the RHS.

Equation: $n+5=19$ , Value: $n=1$
LHS = $1+5$ = $6$

RHS = $19$

Since $6 \neq 19$ , $n=1$ is not the solution.
Equation: $7n+5=19$ , Value: $n=-2$
LHS = $7(-2)+5$ = $-14+5$ = $-9$

RHS = $19$

Since $-9 \neq 19$ , $n=-2$ is not the solution.
Equation: $7n+5=19$ , Value: $n=2$
LHS = $7(2)+5$ = $14+5$ = $19$

RHS = $19$

Since $19 = 19$ , $n=2$ is the solution.
Equation: $4p-3=13$ , Value: $p=1$
LHS = $4(1)-3$ = $4-3$ = $1$

RHS = $13$

Since $1 \neq 13$ , $p=1$ is not the solution.
Equation: $4p-3=13$ , Value: $p=-4$
LHS = $4(-4)-3$ = $-16-3$ = $-19$

RHS = $13$

Since $-19 \neq 13$ , $p=-4$ is not the solution.
Equation: $4p-3=13$ , Value: $p=0$
LHS = $4(0)-3$ = $0-3$ = $-3$

RHS = $13$

Since $-3 \neq 13$ , $p=0$ is not the solution.

Common mistakes

Errors in arithmetic calculations during substitution.
Confusing LHS and RHS when checking solutions.
Incorrectly concluding if an equation is satisfied.
Mistakes in handling negative numbers during substitution.

Revision tips

Practice substituting values carefully, paying attention to signs.
Always compare the calculated LHS with the given RHS to confirm the solution.
Redo the table completion exercise to reinforce the concept of satisfying an equation.
Try to solve the equations yourself before checking the given values.

Practice MCQs

Q1. In the equation x + 3 = 0, if x = 3, is the equation satisfied?

Q2. For the equation x - 7 = 1, which value of x satisfies it?

Q3. If 5x = 25, what value of x makes the equation true?

Q4. In the equation m/3 = 2, if m = 6, is the equation satisfied?

Q5. For the equation 7n + 5 = 19, what is the result of substituting n = 2?

Frequently asked questions

What is a simple equation?

A simple equation is an algebraic equation involving only one variable, with the highest power of the variable being 1. For example, x + 3 = 0 or 7n + 5 = 19.

How do I check if a value is a solution to an equation?

To check if a value is a solution, substitute that value for the variable in the equation. If the Left Hand Side (LHS) equals the Right Hand Side (RHS) after substitution, then the value is a solution.

What does it mean for an equation to be satisfied?

An equation is satisfied when the value of the variable makes the statement true, meaning the expression on the Left Hand Side (LHS) evaluates to the same value as the Right Hand Side (RHS).

Are these NCERT Solutions for Class 7 Maths Chapter 4 helpful for exams?

Yes, these solutions provide clear, step-by-step explanations for all exercises, helping students understand the concepts of simple equations and how to verify solutions, which is essential for exam preparation.

What is the difference between LHS and RHS in an equation?

LHS stands for Left Hand Side, which is the expression on the left of the equals sign (=) in an equation. RHS stands for Right Hand Side, which is the expression on the right of the equals sign.

Content reviewed by the NCERT Help team. Editorial Team and update policy

NCERT Solutions PDF PDF on NCERT Help. URL unchanged for search indexing.