Question 3: Check that the ratio ke2/G msub>e/sub>msub>p/sub> is dim Chapter 1: Electric Charges and Fields Physics Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 3: Check that the ratio ke2/G memp is dimensionless. Look up a Table of physical constants and determine the value of this ratio. What does the ratio signify? is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 1 absolutely free. NCERT Solutions for class 12 Physics Chapter 1: Electric Charges and Fields is very essencial for getting good marks in CBSE Board examinations
Question 3: Check that the ratio ke2/G memp is dimensionless. Look up a Table of physical constants and determine the value of this ratio. What does the ratio signify?
Solution:
Use the table of physical constants we get
Unit of
G = N m2 kg−2.
me = Kg
mp = Kg (Masses of electron and proton)
e = C (e is electric charge)
k = 1/4πε0 = Nm2C-2
Plug the values of the units, we get
= N0m0C0Kg0
All units have canceled out hence it is a ratio, because ratio has no unit
Values of all variable or constant
Charge in electron , e = 6 × 10−19 C
Gravitational constant G = 6.67 × 10−11 N m2 kg-2
Mass of electron, me= 9.1 × 10−31 kg
Mass of proton , mp = 1.66 × 10−27 kg
Plug the values
Ratio is nearly equal to 2.3 × 10 39.
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