NCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions — Exercise 2.2

Prove the following:

Question 1:3sin–1 x = sin–1 (3x – 4x3), 1 1 – , 2 2 x
 Î   

Question 2:3cos–1 x = cos–1 (4x3 – 3x), 1 , 1 2 x
 Î   

ncert class 12 maths chapter 2 Inverse Trigonometric Functions

Question 3:tan–1 1 1 2 7 1 tan tan 11 24 2 − − + =

exercise 2.2 maths class 12 Chapter 2 Inverse Trigonometric Functions

Question 4:1 1 1 1 1 31 2 tan tan tan 2 7 17 − − − + = Write the following functions in the simplest form:

Question 5:2 1 1 1 tan x x − + − , x ¹ 0

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Question 6:1 2 1 tan x 1 − − , |x| > 1

Class 12 maths solutions Inverse Trigonometric Functions

Question 7:1 1 cos tan 1 cos x x −  − 

 +  , 0 < x < π

Question 8:1 cos sin tan cos sin x x x x −  − 

 +  , 4 −p < x < 3 4 p

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Question 9:1 2 2 tan x a x − − , |x| < a

Inverse Trigonometric Functions Class 12 ncert solutions

Question 10:2 3 1 3 2 3 tan 3 a x x a ax −

−     −  , a > 0; 3 3 − < < a a x Find the values of each of the following:

Question 11:–1 –1 1 tan 2cos 2sin 2
      

Question 12:cot (tan–1a + cot–1a)

Exercise 2.2 class 12 Math ncert solutions Chapter 2

Question 13:2 –1 –1 2 2 1 2 1 tan sin cos 2 1 1 x y x y
−   +   + +  , | x | < 1, y > 0 and xy < 1

Question 14:If sin –1 1 –1 sin cos 1 5 x

  + =   , then find the value of x

Prove the following: 1. 3sin1 x = sin1 (3x

Question 15:If –1 1 –1 1 tan tan 2 2 4 x x x x − + p + = − + , then find the value of x Find the values of each of the expressions in Exercises 16 to 18

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Question 16:–1 2 sin sin 3

π     

Question 17:–1 3 tan tan 4

π     

Inverse Trigonometric Functions Math ncert solution class 12

Question 18:–1 3 –1 3 tan sin cot 5 2

  +   

Inverse Trigonometric Functions ncert solutions class 12

Question 19:1 7 cos cos is equal to 6 − π      (A) 7 6 p (B) 5 6 p (C) 3 p (D) 6 p

Question 20:1 1 sin sin ( ) 3 2

π −   − −    is equal to (A) 1 2 (B) 1 3 (C) 1 4 (D) 1

CBSE NCERT Solutions For Class 12 Inverse Trigonometric Functions

Question 21:1 1 tan 3 cot ( 3) − − − − is equal to (A) π (B) 2 p − (C) 0 (D) 2 3