NCERT Solutions · Class 10

NCERT Solutions for Class 10 Maths Chapter 8 Introduction To Trigonometry — Exercise 8.3

Step-by-step NCERT Solutions for Class 10 Maths Chapter 8 (Introduction To Trigonometry), Exercise 8.3. 7 questions with answers — read online free on NCERT Help.

Maths Chapter 8 Exercise 8.3 7 questions
ClassClass 10
SubjectMaths
ChapterChapter 8 — Introduction To Trigonometry
ExerciseExercise 8.3
Questions solved7

Exercises in this chapter

Questions & step-by-step answers

EXERCISE 8.3

NCERT class 10 maths chapter 8 Introduction To Trigonometry

Question 1:Evaluate : (i) sin 18 cos 72 ° ° (ii) tan 26 cot 64 ° ° (iii) cos 48° – sin 42° (iv) cosec 31° – sec 59°

Exercise 8.3 maths class 10 Chapter 8 Introduction To Trigonometry

Question 2:Show that : (i) tan 48° tan 23° tan 42° tan 67° = 1 (ii) cos 38° cos 52° – sin 38° sin 52° = 0

CBSE class 10 maths ncert solutions Chapter 8

Question 3:If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.

class 10 maths solutions Introduction To Trigonometry

Question 4:If tan A = cot B, prove that A + B = 90°.

NCERT class 10 chemistry chapter 8 exercise solutions

Question 5:If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.

Introduction To Trigonometry class 10 ncert solutions

Question 6:If A, B and C are interior angles of a triangle ABC, then show that B + C sin 2       = A cos 2 ×

Question 7:Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.

About this exercise

NCERT Solutions for Class 10 Chapter 8 Ex8.3 Introduction To Trigonometry

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How many questions are solved in Exercise 8.3?

This page includes 7 NCERT textbook questions with detailed answers.

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