NCERT class 10 maths chapter 6 Triangles
Question 1:In Fig. 6.56, PS is the bisector of Ð QPR of D PQR. Prove that QS PQ SR PR = × Fig. 6.56 Fig. 6.57
Exercise Optional maths class 10 Chapter 6 Triangles
Question 2:In Fig. 6.57, D is a point on hypotenuse AC of D ABC, such that BD ^ AC, DM ^ BC and DN ^ AB. Prove that : (i) DM2 = DN . MC (ii) DN2 = DM . AN
CBSE class 10 maths ncert solutions Chapter 6
Question 3:In Fig. 6.58, ABC is a triangle in which Ð ABC > 90° and AD ^ CB produced. Prove that AC2 = AB2 + BC2 + 2 BC . BD. Fig. 6.58 Fig. 6.59
class 10 maths solutions Triangles
Question 4:In Fig. 6.59, ABC is a triangle in which Ð ABC < 90° and AD ^ BC. Prove that AC2 = AB2 + BC2 – 2 BC . BD.
NCERT class 10 chemistry chapter 6 exercise solutions
Question 5:In Fig. 6.60, AD is a median of a triangle ABC and AM ^ BC. Prove that : (i) AC2 = AD2 + BC . DM + 2 BC 2 (ii) AB2 = AD2 – BC . DM + 2 BC 2 (iii) AC2 + AB2 = 2 AD2 + 1 2 BC2
Triangles class 10 ncert solutions
Question 6:Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides.
class 10 Maths NCERT Solutions Chapter 6 Triangles Exercise Optional
Question 7:In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that : (i) D APC ~ D DPB (ii) AP . PB = CP . DP Fig. 6.61 Fig. 6.62
Exercise Optional class 10 Math ncert solutions Chapter 6
Question 8:In Fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. Prove that (i) D PAC ~ D PDB (ii) PA . PB = PC . PD
EXERCISE 6.6 (Optional)*1. In Fig. 6.56, PS is the
Question 9:In Fig. 6.63, D is a point on side BC of D ABC such that BD AB CD AC = × Prove that AD is the bisector of Ð BAC.
Question 10:Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string (from the tip of her rod to the fly) is taut, how much string does she have out (see Fig. 6.64)? If she pulls in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds?