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A Battery of 9 V is Connected in Series With Resistors of 0.2 ? Exercise Chapter 12 Electricity Science Class 10 NCERT

A battery of 9 V is connected in series with resistors of 0.2 ? Chapter 12: Electricity Science Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Q 9: A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor? is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 12 absolutely free. NCERT Solutions for class 10 Science Chapter 12: Electricity is very essencial for getting good marks in CBSE Board examinations

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Q 9: A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?
Ans:
There is no current division occurring in a series circuit. Current flow through the component is the same.
Resistances are connected in series. Hence, the sum of the resistances will give the value of R. R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω
Potential difference, V = 9 V
$I = {V over R} = {{9V} over {13.4Omega }} = 0.671A$
∴ the current that would flow through the 12 Ω resistor will be 0.671 A.

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