Question 2: The electrostatic force on a small sphere of charge 0.4 µC due to anot Chapter 1: Electric Charges and Fields Physics Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 2: The electrostatic force on a small sphere of charge 0.4 µC due to another small sphere of charge − 0.8 µC in air is 0.2 N. (a) What is the distance between the two spheres? (b) What is the force on the second sphere due to the first? is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 1 absolutely free. NCERT Solutions for class 12 Physics Chapter 1: Electric Charges and Fields is very essencial for getting good marks in CBSE Board examinations
Question 2: The electrostatic force on a small sphere of charge 0.4 µC due to another small sphere of charge − 0.8 µC in air is 0.2 N. (a) What is the distance between the two spheres? (b) What is the force on the second sphere due to the first?
Solution:
(a) What is the distance between the two spheres?
Given that
Charge on first small sphere, q1 = 0.4 µC = 0.4 × 10−6 C
Charge on second small sphere, q2 = − 0.8 µC = − 0.8 × 10−6 C
(1µC = 10 –6C so multiply by 10-6 there)
The electrostatic force on a small sphere, F = 0.2 N
Apply Coulomb’s law
q1 = first charge
q2 = Second charge
r = distance between both charge
ε0= permittivity of free space
1/4πε0 = 9 × 109 Nm2C-2
Plug the values we get
The distance between the two spheres is 0.12 m.
(b) What is the force on the second sphere due to the first?
Both charge will attract each other with the same force. Hence, attraction force on the second charged sphere due to the first charged sphere is 0.2 N.
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