Ncert Solutions for class 12 subject Maths Chapter 8 APPLICATION OF INTEGRALSin pdf Best Free NCERT Solutions for class 1 to 12 in pdf NCERT Solutions, cbse board, Maths, ncert Solutions for Class 12 Maths, class 12 Maths ncert solutions, APPLICATION OF INTEGRALS, Class 12, ncert solutions chapter 8 APPLICATION OF INTEGRALS, class 12 Maths, class 12 Maths ncert solutions, Maths ncert solutions class 12, Ncert Solutions Class 12 Mathematics Chapter 8 APPLICATION OF INTEGRALS

**1. Find the area of the region bounded by the curve y^2 =x and the lines x = 1 , x = 4 and the x axis **

**2.Find the area of the region bounded by y^2 = 9x, x=2, x =4 and the x axis in the first quadrant.**

**Find the equation of the region bounded by the ellipse x^2/16 + y^2/9 =1**

**Find the equation of the region bounded by the ellipse x^2/4 + y^2/9 =1**

**6. find the area of the region in the first quadrant enclosed by x axis, line x =root 3 y and the circle x^2 + y^2 = 4**

**7.Area between x=y2 and x=4 is divided in two equal parts by the line x = a, find the value of a**

**8. The area between x^2 = y
and x = 4 is divided into two equal parts by the line x = a, find the value of a.**

**9. Find the area of the region bounded by the parabola y = x^2 and y= |x|**

**10. Find the area bounded by the curve x^2 =4y and the line x = 4y- 2 **

**11. Find the area of the region bounded by the curve y2 = 4x and the line x = 3.
**

**12. Area lying in the first quadrant and bounded by the circle x2 + y = 4 and the lines
x = 0 and x = 2 is
2
**

**13. Area of the region bounded by the curve y^2 =4x , y axis and the line y=3 is **

**1. Find the area of the circle 4x^2 + 4y^2 = 9 which is interior to the parabola x^2 =4y**

**2. Find the area bounded by curves (x – 1)^2 + y^2 = 1 and x^2 + y^2 = 1**

**3.Find the area of the region bounded by the curves y= x^2 + 2 , y=x , x =0 and x = 3**

**4.Using integration find the area of region bounded by the triangle whose vertices are (– 1, 0), (1, 3) and (3, 2).**

**5. Using integration find the area of the triangular region whose sides have the equations y = 2x + 1, y = 3x + 1 and x = 4.**

**6. Smaller area enclosed by the circle x^2 +y^2 = 4 and the lines x + y = 2 is
(A) 2 (π – 2) (B) π – 2 (C) 2π – 1 (D) 2 (π + 2)**

**7. Area lying between the curves y^2 = 4x and y = 2x is**

**1. Find the area under the given curves and given lines
(i) y = x^2 , x=1 , x= 2 and x axis
(ii) y = x^4 , x=1 , x= 5 and x axis**

** 2. Find the area between the curves y = x and y = x^2**

**3.Find the area of the region lying in the first quadrant and bounded by y = 4x^2, x=0, y=1 and y= 4**

**4. Sketch the graph of y = x + 3 and evaluate integration limits 6 to 0 of x + 3 dx**

**5. Find the area bounded by the curve y = sin x between x = 0 and x = 2π.
**

**6. Find the area enclosed between the parabola y^2 = 4ax and the line y =mx**

**7. Find the area enclosed by the parabola 4y = 3x^2 and the line 2y = 3x + 12 using integration to find area,**

**8. Find the area of the smaller region bounded by the ellipse x^2/9 + y^2/4 = 1 and the line x/3 + y/2 =1 **

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