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NCERT Solutions For Class 12 Maths Chapter 2 Inverse Trigonometric Functions Exercise Miscellaneous Question 1 to 17 Answer: Downlaod pdf

Find the value of the following: 1. 1 13 cos cos 6 p 2. 1 7 tan tan 6 p Prove that 3. 1 3 1 24 2sin tan 5 7 = 4. 1 8 1 3 1 77 sin sin tan 17 5 36 + = 5. 1 4 1 12 1 33 cos cos cos 5 13 65 + = 6. 1 12 1 3 1 56 cos sin sin 13 5 65 + = 7. 1 63 1 5 1 3 tan sin cos 16 13 5 = + 8. 1 1 1 1 1 1 1 1 tan tan tan tan 5 7 3 8 4 p Prove that 9. 1 1 1 1 tan cos 2 1 x x x = + , x [0, 1] 10. 1 1 sin 1 sin cot 1 sin 1 sin 2 x x x x x + + = + , 0, 4 x p 11. 1 1 1 1 1 tan cos 1 1 4 2 x x x x x + p = + + , 1 1 2 x [Hint: Put x = cos 2q] 12. 9 9 1 1 9 1 2 2 sin sin 8 4 3 4 3 p = Solve the following e

Miscellaneous  Class 12 Math Chapter 2 ncert solutions

Other EXERCISE for Class 12 Chapter 2 Inverse Trigonometric Functions NCERT Solutions




Find the value of the following:

Question 1: –1 13 cos cos 6 Ο€     

ncert class 12 maths chapter 2 Inverse Trigonometric Functions

Question 2: –1 7 tan tan 6 Ο€      Prove that

exercise Miscellaneous maths class 12 Chapter 2 Inverse Trigonometric Functions

Question 3: –1 3 –1 24 2sin tan 5 7 =

Question 4: –1 8 –1 3 –1 77 sin sin tan 17 5 36 + =

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Question 5: –1 4 –1 12 –1 33 cos cos cos 5 13 65 + =

Class 12 maths solutions Inverse Trigonometric Functions

Question 6: –1 12 –1 3 –1 56 cos sin sin 13 5 65 + =

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Question 7: –1 63 –1 5 –1 3 tan sin cos 16 13 5 = +

Inverse Trigonometric Functions Class 12 ncert solutions

Question 8: –1 1 1 1 1 1 1 1 tan tan tan tan 5 7 3 8 4 βˆ’ βˆ’ βˆ’ p Prove that

Question 9: –1 1 –1 1 tan cos 2 1 x x x βˆ’ = + , x Î [0, 1]

Class 12 Maths NCERT Solutions Chapter 2 Inverse Trigonometric Functions Exercise Miscellaneous

Question 10:–1 1 sin 1 sin cot 1 sin 1 sin 2 x x x x x + + βˆ’   =  + βˆ’ βˆ’  , 0, 4 x Ο€  Î   

Exercise Miscellaneous class 12 Math ncert solutions Chapter 2

Question 11:–1 1 1 1 –1 tan cos 1 1 4 2 x x x x x + βˆ’ βˆ’  p  = βˆ’  + + βˆ’  , 1 1 2 βˆ’ ≀ x ≀ [Hint: Put x = cos 2q]

Find the value of the following: 1. 1 13

Question 12:9 9 1 1 9 1 2 2 sin sin 8 4 3 4 3 Ο€ βˆ’ βˆ’ βˆ’ = Solve the following equations:

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Question 13:2tan–1 (cos x) = tan–1 (2 cosec x)

Inverse Trigonometric Functions Math ncert solution class 12

Question 14: –1 1 1 –1 tan tan ,( 0) 1 2 x x x x βˆ’ = > +

Question 15:sin (tan–1 x), | x| < 1 is equal to (A) 2 1 x βˆ’ x (B) 2 1 1βˆ’ x (C) 2 1 1+ x (D) 2 1 x + x

Inverse Trigonometric Functions ncert solutions class 12

Question 16:sin–1 (1 – x) – 2 sin–1 x = 2 p , then x is equal to (A) 0, 1 2 (B) 1, 1 2 (C) 0 (D) 1 2

CBSE NCERT Solutions For Class 12 Inverse Trigonometric Functions

Question 17: 1 1 tan tan x x y y x y βˆ’  βˆ’ βˆ’   βˆ’   + is equal to (A) 2 p (B) 3 p (C) 4 p (D) 3 4 βˆ’ p

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