CBSE Class 6 Mathematics Chapter 2: Whole Numbers NCERT Solutions

To find the next three natural numbers after 10999, we need to add 1 successively to the given number.

1. The first number after 10999 is found by adding 1: $10,999\; +\; 1\; =\; 11,000$
2. The second number after 10999 is found by adding 1 to the previous result: $11,000\; +\; 1\; =\; 11,001$
3. The third number after 10999 is found by adding 1 to the previous result: $11,001\; +\; 1\; =\; 11,002$

Therefore, the next three natural numbers after 10999 are 11,000, 11,001, and 11,002.

To find the three whole numbers occurring just before 10001, we need to subtract 1 successively from the given number.

1. The whole number just before 10001 is found by subtracting 1: $10,001\; -\; 1\; =\; 10,000$
2. The next whole number before that is found by subtracting 1 from the previous result: $10,000\; -\; 1\; =\; 9,999$
3. The third whole number before that is found by subtracting 1 from the previous result: $9,999\; -\; 1\; =\; 9,998$

Thus, the three whole numbers occurring just before 10001 are 10,000, 9,999, and 9,998.

The set of whole numbers includes 0 and all positive integers (1, 2, 3, ...). When we list these numbers in increasing order, 0 comes first. Therefore, 0 is the smallest whole number.

To find the number of whole numbers between two given numbers, we subtract the smaller number from the larger number and then subtract 1 from the result. This is because we are looking for numbers strictly between them, not including the endpoints.

The larger number is 53 and the smaller number is 32.

Number of whole numbers = (Larger number - Smaller number) - 1

= $53\; -\; 32\; -\; 1$

= $21\; -\; 1$

= $20$

Therefore, there are 20 whole numbers between 32 and 53.

The successor of a whole number is the number obtained by adding 1 to it. We will find the successor for each given number:

(a) The successor of 2440701 is $2440701\; +\; 1\; =\; 2440702$.

(b) The successor of 100199 is $100199\; +\; 1\; =\; 100200$.

(c) The successor of 1099999 is $1099999\; +\; 1\; =\; 1100000$.

(d) The successor of 2345670 is $2345670\; +\; 1\; =\; 2345671$.

The predecessor of a whole number is the number obtained by subtracting 1 from it. We will find the predecessor for each given number:

(a) The predecessor of 94 is $94\; -\; 1\; =\; 93$.

(b) The predecessor of 10000 is $10000\; -\; 1\; =\; 9999$.

(c) The predecessor of 208090 is $208090\; -\; 1\; =\; 208089$.

(d) The predecessor of 7654321 is $7654321\; -\; 1\; =\; 7654320$.

On a number line, numbers are arranged in increasing order from left to right. This means that a smaller number is always to the left of a larger number. We will compare each pair and determine which number is on the left.

(a) Comparing 530 and 503: We see that $530\; >\; 503$. Therefore, 503 is smaller and appears on the left side of 530 on the number line.

(b) Comparing 370 and 307: We see that $370\; >\; 307$. Therefore, 307 is smaller and appears on the left side of 370 on the number line.

(c) Comparing 98765 and 56789: We see that $98765\; >\; 56789$. Therefore, 56789 is smaller and appears on the left side of 98765 on the number line.

(d) Comparing 9830415 and 10023001: We see that . Therefore, 9830415 is smaller and appears on the left side of 10023001 on the number line.