CBSE Class 11 Physics Chapter 3: Motion in a Straight Line NCERT Solutions

NCERT Solutions PDF Class 11 PDF

This resource provides detailed NCERT Solutions for Class 11 Physics, Chapter 3, focusing on Motion in a Straight Line. It clarifies concepts such as identifying when an object can be treated as a point object, analyzing motion using position-time graphs, and understanding relative speeds. The solutions break down complex problems into understandable steps, helping students grasp the nuances of one-dimensional motion. This guide is essential for students preparing for their board examinations, offering clear explanations and accurate answers to reinforce learning and build confidence in tackling physics problems related to kinematics.

Quick info

BoardCBSE
ClassClass 11
SubjectPhysics
Session2026
LanguageEnglish
TypeNCERT Solutions
ChapterChapter 3: Motion in a Straight Line

Chapter summary

Chapter 3 of the NCERT Class 11 Physics syllabus deals with Motion in a Straight Line. These solutions cover key concepts like the definition of a point object and its application in real-world scenarios. It also delves into interpreting position-time graphs to determine relative distances, starting times, speeds, and overtaking instances between two objects. The exercises are designed to build a strong foundation in understanding one-dimensional kinematics.

Learning outcomes

  • Understand the conditions under which an object can be approximated as a point object.
  • Interpret position-time graphs to analyze motion.
  • Determine relative distances of objects from a reference point.
  • Compare the starting times of motion for different objects.
  • Calculate and compare the speeds of objects from their x-t graphs.
  • Identify instances of overtaking in one-dimensional motion.

Topics covered

Paper topics

  • Point Object Approximation
  • Position-Time Graphs
  • Analysis of x-t Graphs
  • Relative Distance from School
  • Starting Time of Motion
  • Speed from x-t Graph
  • Overtaking in One Dimension
  • Interpreting Graphical Data

Important topics

  • Point Object Concept
  • Position-Time Graph Interpretation
  • Calculating Speed from x-t Graphs
  • Determining Relative Positions and Times
  • Identifying Overtaking Events

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Questions and Solutions

Question 3.1

In which of the following examples of motion can the body be considered approximately a point object:
  1. A railway carriage moving without jerks between two stations.
  2. A monkey sitting on top of a man cycling smoothly on a circular track.
  3. A spinning cricket ball that turns sharply on hitting the ground.
d) A tumbling beaker that has slipped off the edge of a table.
Solution:

An object can be considered a point object if its size is negligible compared to the distances it travels or the scale of the phenomenon being observed. Let's analyze each case:

  1. A railway carriage moving without jerks between two stations: The distance between two stations is typically very large compared to the dimensions of a railway carriage. Therefore, the carriage can be reasonably approximated as a point object for this motion.
  2. A monkey sitting on top of a man cycling smoothly on a circular track: The radius of a circular track is usually much larger than the size of a monkey or a person. Thus, the monkey can be treated as a point object relative to the track's dimensions.
  3. A spinning cricket ball that turns sharply on hitting the ground: The distance over which a cricket ball turns sharply after hitting the ground is comparable to the size of the ball itself. Therefore, the ball cannot be considered a point object in this scenario, as its rotation and spin are significant.
  4. A tumbling beaker that has slipped off the edge of a table: The distance the beaker falls is often comparable to its own dimensions, especially if it's a short fall. Thus, it cannot be accurately represented as a point object.

Based on this analysis, the correct options are (a) and (b).

Question 3.2

The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively are shown in Fig. 3.19. Choose the correct entries in the brackets below;
  1. (A/B) lives closer to the school than (B/A)
b) (A/B) starts from the school earlier than (B/A) c) (A/B) walks faster than (B/A) d) A and B reach home at the (same/different) time e) (A/B) overtakes (B/A) on the road (once/twice).
Solution:

Let's analyze the provided position-time (x-t) graphs to determine the correct statements.

  1. (A) lives closer to the school than (B).

    The graph shows the position (x) versus time (t). The school is at the origin (x=0). The final position of child A (home P) is closer to the origin than the final position of child B (home Q). Therefore, A lives closer to the school.

  2. (A) starts from the school earlier than (B).

    The graph indicates that child A's journey starts at time t=0 (the graph begins at the origin). Child B's journey starts at a later time, as their graph begins at a positive value of t when x=0. Thus, A starts earlier.

  3. (B) walks faster than (A).

    The speed of an object is represented by the slope of its position-time graph. Observing the graph, the slope of B's line is steeper than the slope of A's line. A steeper slope signifies a higher speed. Therefore, B walks faster than A.

  4. A and B reach home at the same time.

    Both graphs end at the same point on the time axis. This indicates that both children reach their respective homes at the same final time, even though they started at different times and traveled at different speeds.

  5. (B) overtakes (A) on the road once.

    An overtaking event occurs when the object that started later or was moving slower is overtaken by the object that started earlier or is moving faster, resulting in them being at the same position at the same time. In this graph, B starts later but moves faster. The point where B's graph intersects A's graph represents the moment B catches up to and overtakes A. This intersection occurs only once.

Common mistakes

  • Incorrectly identifying when an object can be treated as a point object.
  • Misinterpreting the slope of the position-time graph.
  • Confusing the starting time from the origin of the x-t graph.
  • Errors in determining overtaking points from the x-t graph.

Revision tips

  • Focus on the conditions for approximating an object as a point object.
  • Practice drawing and interpreting position-time graphs for various scenarios.
  • Pay close attention to the slopes and intercepts of x-t graphs.
  • Review the concept of relative speed and its graphical representation.

Practice MCQs

Q1. Under which condition can a railway carriage moving between two stations be considered a point object?

Q2. In a position-time graph, what does the slope represent?

Q3. If two children start from the same point at different times and one walks faster, when does the faster child overtake the slower one?

Q4. A monkey on a smoothly cycling man on a circular track can be considered a point object if:

Q5. In an x-t graph, if object A starts at t=0 and object B starts at a later time t > 0, who starts earlier?

Frequently asked questions

What is a point object in physics?

A point object is an object whose size is negligible compared to the distances it travels or the scale of the motion being considered. For example, a train moving between two distant cities can be treated as a point object.

How can a position-time graph help understand motion?

A position-time (x-t) graph visually represents an object's position as a function of time. Its slope indicates the object's velocity, and the graph can reveal starting times, ending times, and instances where objects might overtake each other.

How do I determine which object is closer to the school from an x-t graph?

The object whose position-time graph shows a smaller final position value (closer to the origin, assuming the school is at x=0) is closer to the school.

What does it mean if the slope of one x-t graph is steeper than another?

A steeper slope on a position-time graph indicates a higher speed. Therefore, the object with the steeper slope is moving faster than the object with the less steep slope.

How can I tell if two objects reach their destination at the same time from an x-t graph?

If the position-time graphs for two objects end at the same time value on the x-axis, it means they reach their respective destinations simultaneously.

What is the significance of the intersection point of two x-t graphs?

An intersection point on the position-time graphs of two objects signifies that both objects are at the same position at the same instant in time. This is the point where one object overtakes the other.

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