CBSE Class 10 Science The Human Eye and The Colourful World NCERT Solutions

NCERT Solutions PDF Class 10 PDF

CBSE Class 10 Science, Chapter 11, "The Human Eye and The Colourful World," offers clear explanations of how we see and the fascinating world of light. This chapter explores common vision problems like myopia (nearsightedness) and hypermetropia (farsightedness), detailing what causes them and how eyeglasses with specific lenses can correct them. You'll also learn about the magic of light dispersion, understanding how a prism splits white light into a beautiful rainbow of colors. The solutions explain why the sun looks white overhead at midday, relating it to how light scatters in the atmosphere. These resources are designed to build a strong foundation in optics and the workings of the human eye, providing practical ways to tackle problems and prepare effectively for exams.

Quick info

BoardCBSE
ClassClass 10
SubjectScience (Exemplar)
Session2026
LanguageEnglish
TypeNCERT Solutions
Chapter11. The Human Eye and The Colourful World

Chapter summary

Chapter 11 of the CBSE Class 10 Science NCERT Solutions focuses on "The Human Eye and The Colourful World." It addresses common vision defects such as myopia (nearsightedness) and hypermetropia (farsightedness), explaining how they are corrected with lenses of specific powers. The chapter also explores the dispersion of white light by a prism, detailing the spectrum of colors formed and the reasons behind atmospheric phenomena like the color of the sky and the sun's appearance at noon. These solutions provide clear explanations for MCQs and conceptual questions.

Learning outcomes

  • Understand the causes and corrections for myopia and hypermetropia.
  • Calculate the power of a lens required to correct vision defects.
  • Explain the phenomenon of dispersion of white light through a prism.
  • Identify the order of colors in the visible spectrum.
  • Explain the scattering of light and its effect on the apparent color of the sun and sky.

Topics covered

Paper topics

  • Human Eye Defects
  • Myopia
  • Hypermetropia
  • Lens Power
  • Concave Lenses
  • Dispersion of Light
  • Prism
  • Visible Spectrum
  • Scattering of Light
  • Atmospheric Optics

Important topics

  • Correction of Myopia and Hypermetropia
  • Lens Power Calculation
  • Dispersion of White Light by Prism
  • Scattering and its effect on Sun's color

PDF preview

Read page by page below. PDF is streamed from the official NCERT website — no download button on this page.

Loading document …
Page of
Loading page …

Questions and Solutions

Multiple Choice Questions - 1

1. A person cannot see distinctly objects kept beyond 2 m. This defect can be corrected by using a lens of power

(a) + 0.5 D

(b) - 0.5 D

(c) + 0.2 D

(d) - 0.2 D

Solution:

The person is experiencing myopia (nearsightedness) because they cannot see distant objects clearly. Myopia occurs when the eye's focal length is too long or the eyeball is too long, causing light to focus in front of the retina instead of on it. This defect is corrected using a concave lens, which diverges light rays before they enter the eye, effectively reducing the eye's overall focusing power. The power of a lens is given by the formula P = \frac{1}{f}, where f is the focal length in meters. If the person cannot see beyond 2 meters, it means their far point is 2 meters. To correct this, we need a lens that can form a virtual image of an object at infinity at this far point of 2 meters. Thus, the required focal length is f = -2 m (negative for a concave lens). The power of the lens is then P = \frac{1}{-2\text{ m}} = -0.5 D. Therefore, a lens with a power of -0.5 D is required.

The correct option is (b).

Multiple Choice Questions - 2

2. A student sitting on the last bench can read the letters written on the blackboard but is not able to read the letters written in his text book. Which of the following statements is correct?

(a) The near point of his eyes has receded away

(b) The near point of his eyes has come closer to him

(c) The far point of his eyes has come closer to him

(d) The far point of his eyes has receded away

Solution:

The student can read the blackboard, which is a distant object, indicating that their far point is normal or adequate. However, they cannot read the textbook, which is a nearby object. This suggests that the near point of their eyes has shifted further away from the eye than the standard 25 cm. This condition is known as hypermetropia (farsightedness). In hypermetropia, the eye's ability to focus on near objects is diminished because the near point has receded. To read the textbook properly, the student would need to hold it further away or use corrective lenses (convex lenses) that increase the converging power of the eye's optical system.

The correct statement is (a).

Multiple Choice Questions - 3

3. A prism ABC (with BC as base) is placed in different orientations. A narrow beam of white light is incident on the prism as shown in Figure 11.1. In which of the following cases, after dispersion, the third colour from the top corresponds to the colour of the sky? The Human Eye and the Colourful World

(a) (i)

(b) (ii)

(c) (iii)

(d) (iv)

Solution:

The phenomenon described is the dispersion of white light by a prism. When white light passes through a prism, it splits into its constituent colors (VIBGYOR - Violet, Indigo, Blue, Green, Yellow, Orange, Red) due to different refractive indices of the prism material for different wavelengths of light. Violet light bends the most, and red light bends the least. The color of the sky is typically blue. We need to determine the orientation of the prism that results in blue being the third color from the top in the dispersed spectrum. In the given figure, case (ii) shows the prism oriented with its base BC at the top. When white light enters such a prism, the colors disperse, with violet bending the most and red the least. The order of colors from the top (least deviated) to the bottom (most deviated) would be Red, Orange, Yellow, Green, Blue, Indigo, Violet. In this arrangement, Blue is indeed the third color from the top.

The correct option is (b).

Multiple Choice Questions - 4

4. At noon the sun appears white as

(a) light is least scattered

(b) all the colours of the white light are scattered away

(c) blue colour is scattered the most

(d) red colour is scattered the most

Solution:

At noon, the sun is almost directly overhead. This means that sunlight travels through the least amount of Earth's atmosphere to reach our eyes. The scattering of light, particularly the shorter blue wavelengths, is responsible for the sky appearing blue during other times of the day. However, when the sun is at its zenith, the path length through the atmosphere is minimal. While some scattering still occurs, it is not significant enough to remove all the colors or preferentially scatter blue light away to the extent that it colors the sun. Consequently, the sunlight reaches us relatively unscattered, and we perceive it as white light, which is the combination of all colors.

The correct option is (b), interpreted as the differential scattering that colors the sky is minimized, allowing the white light to dominate our perception of the sun.

Common mistakes

  • Confusing myopia with hypermetropia and their respective lens corrections.
  • Incorrectly applying the lens formula or power formula.
  • Misunderstanding the direction of light dispersion in a prism based on its orientation.
  • Confusing scattering with dispersion of light.

Revision tips

  • Review the definitions and correction methods for myopia and hypermetropia.
  • Practice calculating lens power using the given focal length.
  • Visualize the dispersion of white light through a prism and the resulting spectrum.
  • Understand the role of light scattering in atmospheric color phenomena.

Practice MCQs

Q1. A person is unable to see objects clearly when they are placed beyond 2 meters. What type of lens is needed to correct this vision defect, and what is its power?

Q2. A student can read the blackboard from the last bench but struggles to read their textbook. Which statement accurately describes this condition?

Q3. When a prism is oriented with its base BC at the top, and white light is passed through it, which color will appear third from the top in the dispersed spectrum?

Q4. At midday, the sun appears white. What is the primary reason for this observation?

Frequently asked questions

What is myopia and how is it corrected?

Myopia, or nearsightedness, is a vision defect where a person cannot see distant objects clearly. It is corrected using a concave lens, which has a negative power, to diverge the light rays before they enter the eye.

What is hypermetropia and how is it corrected?

Hypermetropia, or farsightedness, is a vision defect where a person cannot see nearby objects clearly. It is corrected using a convex lens, which has a positive power, to converge the light rays more strongly before they enter the eye.

What is the power of a lens needed to correct myopia where the far point is 2m?

The power (P) is the reciprocal of the focal length (f) in meters. For myopia with a far point of 2m, the focal length needed is -2m (since it's a concave lens). Therefore, P = 1/(-2m) = -0.5 D.

What phenomenon causes white light to split into different colors when passing through a prism?

The splitting of white light into its constituent colors when it passes through a prism is called dispersion. This occurs because different colors of light have different wavelengths and are refracted at slightly different angles by the prism material.

Why does the sun appear white at noon?

At noon, the sun is directly overhead, and its light travels a shorter path through the atmosphere. This minimizes the scattering of blue light, allowing the white light from the sun to reach our eyes more directly, making it appear white.

How does the orientation of a prism affect the order of colors in the dispersed spectrum?

The orientation of the prism determines the order of colors. Typically, violet light bends the most and red light bends the least. If the base of the prism is at the bottom, violet is at the bottom of the spectrum. If the base is at the top, violet is at the top, and the order is reversed relative to the base.

Content reviewed by the NCERT Help team. Editorial Team and update policy

NCERT Solutions PDF PDF on NCERT Help. URL unchanged for search indexing.