CBSE Class 12 Physics 2017 Previous Year Board Question Paper (Set-3)
This is the CBSE Class 12 Physics (Theory) Previous Year Question Paper from the 2017 Main Exams, Delhi-Set-3. The paper is for the Hindi medium and carries a maximum of 70 marks, with a duration of 3 hours. It contains a total of 26 questions divided into five sections: Section A (5 questions, 1 mark each), Section B (5 questions, 2 marks each), Section C (12 questions, 3 marks each), Section D (1 value-based question, 4 marks), and Section E (3 questions, 5 marks each). While there is no overall choice, internal choices are provided in one question of two marks, one question of three marks, and all three questions of five marks. Solving this board question paper is crucial for students to understand the exam pattern, question types, and marking scheme, thereby enhancing their preparation and performance in the upcoming CBSE board examinations.
Quick info
| Board | CBSE |
|---|---|
| Class | 12 |
| Subject | Physics |
| Session | 2017 |
| Language | Hindi |
| Type | Previous Year Question Paper |
| Exam type | Board Exam |
Paper pattern
The question paper has 5 sections (A, B, C, D, E) with a total of 26 questions. Section A has 5x1 mark questions, Section B has 5x2 mark questions, Section C has 12x3 mark questions, Section D has 1x4 mark value-based question, and Section E has 3x5 mark questions.
Topics covered
Paper topics
- Electromagnetism
- Optics
- Modern Physics
- Semiconductors
- Electrostatics
- Current Electricity
- Magnetic Effects of Current
- Electromagnetic Induction
- Alternating Current
- Electromagnetic Waves
- Dual Nature of Radiation and Matter
- Atoms and Nuclei
- Electronic Devices
Important topics
- Electrostatics
- Current Electricity
- Moving Charges and Magnetism
- Magnetism and Matter
- Electromagnetic Induction
- Alternating Current
- Electromagnetic Waves
- Ray Optics and Optical Instruments
- Wave Optics
- Dual Nature of Radiation and Matter
- Atoms and Nuclei
- Electronic Devices
PDF preview
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Question paper text
SET - 3
Series: GBM/1
रोल नं.
कोड नं
परीक्षार्थी कोड को उत्तर-पुस्तिका के मुख-पृष्ठ
पर अवश्य लिखें ।
Candidates must write the Code on
the title page of the answer-book.
Roll No.
Code No.
55/1/3
कृपया जाँच कर लें कि इस प्रश्न-पत्र में मुद्रित पृष्ट 16 हैं।
प्रश्न-पत्र में दाहिने हाथ की ओर दिए गए कोड नम्बर को छात्र उत्तर-पुस्तिका के मुख-पृष्ठ पर लिखें ।
कृपया जाँच कर लें कि इस प्रश्न-पत्र में 26 प्रश्न हैं।
कृपया प्रश्न का उत्तर लिखना शुरू करने से पहले, प्रश्न का क्रमांक अवश्य लिखें।
इस प्रश्न-पत्र को पढ़ने के लिए 15 मिनट का समय दिया गया है । प्रश्न-पत्र का वितरण पूर्वाह्न में 10.15 बजे किया जायेगा । 10.15 बजे से 10.30 बजे तक छात्र केवल प्रश्न-पत्र को पढ़ेंगे और इस अवधि के दौरान वे उत्तर-पुस्तिका पर कोई उत्तर नहीं लिखेंगे ।
Please check that this question paper contains 16 printed pages.
Code number given on the right hand side of the question paper should be written on the title page of the answer-book by the candidate.
Please check that this question paper contains 26 questions.
Please write down the Serial Number of the question before attempting it.
15 minute time has been allotted to read this question paper. The question paper will be distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the question paper only and will not write any answer on the answer-book during this period.
DY.COM WWW.TIWARIACADEP
भौतिक विज्ञान (सेद्धान्तिक) PHYSICS (Theory)
निर्धारित समय : 3 घंटे
अधिकतम अंक :70
Time allowed: 3 hours
Maximum Marks: 70
सामान्य निर्देश:
- सभी प्रश्न अनिवार्य हैं । इस प्रश्न-पत्र में कुल 26 प्रश्न हैं ।
- इस प्रश्न-पत्र के 5 भाग हैं : खण्ड-अ, खण्ड-स, खण्ड-स, खण्ड-द और खण्ड-य ।
- प्रश्न हैं, प्रत्येक के 5 अंक हैं।
- गए चयन में से केवल एक प्रश्न ही करना है।
[P.T.O.
55/1/3
(v) <math>c = 3 \times 10^8 \text{ m/s}</math>
<math>h = 6.63 \times 10^{-34} \text{ Js}</math>
<math>e = 1.6 \times 10^{-19} C</math>
<math>\mu_0 = 4\pi \times 10^{-7} \text{ T m A}^{-1}</math>
900013
<math>\varepsilon_0 = 8.854 \times 10^{-12} \,\mathrm{C}^2 \,\mathrm{N}^{-1} \,\mathrm{m}^{-2}</math>
<math>\frac{1}{4\pi\epsilon_0} = 9 \times 10^9 \text{ N m}^2 \text{ C}^{-2}</math>
इलेक्ट्रॉन का द्रव्यमान = <math>9.1 \times 10^{-31} \text{ kg}</math>
न्यूट्रॉन का द्रव्यमान = <math>1.675 \times 10^{-27} \text{ kg}</math>
प्रोटोन का द्रव्यमान = <math>1.673 \times 10^{-27} \text{ kg}</math>
आवोगाद्रो संख्या = <math>6.023 \times 10^{23}</math> प्रति ग्राम मोल
बॉल्ट्ज़मान नियतांक = <math>1.38 \times 10^{-23} \text{ JK}^{-1}</math>
General Instructions:
- All questions are compulsory. There are 26 questions in all.
- This question paper has five sections: Section A, Section B, Section C, Section D and Section E.
- Section A contains five questions of one mark each, Section B contains five questions of two marks each, Section C contains twelve questions of three marks each, Section D contains one value based question of four marks and Section E contains three questions of five marks each.
==-ldIn) There is no overall choice. However, an internal choice has been provided in one question of two marks, one question of three marks and all the three questions of five marks weightage. You have to attempt only one of the choices in such questions.
- You may use the following values of physical constants wherever necessary:
<math>c = 3 \times 10^8 \text{ m/s}</math>
<math>h = 6.63 \times 10^{-34} \text{ Js}</math>
<math>e = 1.6 \times 10^{-19} C</math>
<math>\mu_0 = 4\pi \times 10^{-7} \text{ T m A}^{-1}</math>
<math>\varepsilon_0 = 8.854 \times 10^{-12} \,\mathrm{C}^2 \,\mathrm{N}^{-1} \,\mathrm{m}^{-2}</math>
<math>\frac{1}{4\pi\epsilon_0} = 9 \times 10^9 \text{ N m}^2 \text{ C}^{-2}</math>
Mass of electron = <math>9.1 \times 10^{-31}</math> kg
Mass of neutron = <math>1.675 \times 10^{-27}</math> kg
Mass of proton = <math>1.673 \times 10^{-27}</math> kg
Avogadro's number = <math>6.023 \times 10^{23}</math> per gram mole
Boltzmann constant = <math>1.38 \times 10^{-23} \text{ JK}^{-1}</math>
55/1/3
Frequently asked questions
What is this document?
This document is the CBSE Class 12 Physics (Theory) Previous Year Board Question Paper from the 2017 Main Exams, Delhi-Set-3.
What is the marking scheme and duration?
The paper is for a maximum of 70 marks and has a duration of 3 hours. It is divided into five sections with varying marks per question.
Are there any choices in the questions?
Yes, internal choices are provided in one question of two marks, one question of three marks, and all three questions of five marks.
How does solving this PYQ help students?
Solving this previous year question paper helps students understand the CBSE exam pattern, question difficulty, and time management, leading to better preparation and improved scores.
What is the structure of the Physics 2017 paper?
The paper consists of 26 questions divided into five sections: Section A (1 mark each), Section B (2 marks each), Section C (3 marks each), Section D (4 marks, value-based), and Section E (5 marks each).
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