CBSE Class 11 Chemistry Chapter 9 Hydrogen NCERT Solutions

NCERT Solutions PDF Class 11 PDF

This chapter delves into the fundamental element Hydrogen, providing detailed NCERT Solutions for Class 11 Chemistry students. It covers the unique position of hydrogen in the periodic table, justifying its placement based on electronic configuration and its dual resemblance to alkali metals and halogens. The solutions explain the different isotopes of hydrogen—Protium, Deuterium, and Tritium—and their mass ratios. It further clarifies why hydrogen exists as a diatomic molecule (H₂) rather than a monoatomic form under normal conditions, due to its high ionization enthalpy. The chapter also explores methods for increasing dihydrogen production, specifically through coal gasification and the subsequent water-gas shift reaction. These solutions are designed to offer clear, step-by-step explanations, aiding students in grasping complex concepts and preparing effectively for their examinations.

Quick info

BoardCBSE
ClassClass 11
SubjectChemiry
Session2026
LanguageEnglish
TypeNCERT Solutions
ChapterChapter 9: Hydrogen

Chapter summary

Chapter 9, Hydrogen, focuses on the properties, isotopes, and production of hydrogen. The NCERT Solutions cover the justification for hydrogen's unique position in the periodic table, its diatomic nature, and methods to enhance dihydrogen yield from processes like coal gasification. Key concepts include electronic configuration, isotopes (Protium, Deuterium, Tritium), ionization enthalpy, and the water-gas shift reaction.

Learning outcomes

  • Understand the electronic configuration of hydrogen and its implications.
  • Justify the unique position of hydrogen in the periodic table.
  • Identify and differentiate between the isotopes of hydrogen.
  • Explain the reasons for hydrogen's diatomic molecular form.
  • Describe methods to increase dihydrogen production from coal gasification.

Topics covered

Paper topics

  • Position of Hydrogen in the Periodic Table
  • Electronic Configuration of Hydrogen
  • Resemblance to Alkali Metals
  • Resemblance to Halogens
  • Isotopes of Hydrogen
  • Protium
  • Deuterium
  • Tritium
  • Diatomic Nature of Hydrogen
  • Ionization Enthalpy
  • Coal Gasification
  • Water-Gas Shift Reaction

Important topics

  • Position of Hydrogen in the Periodic Table
  • Isotopes of Hydrogen (Protium, Deuterium, Tritium)
  • Dual Behaviour of Hydrogen
  • Diatomic Nature of Hydrogen (H₂)
  • Production of Dihydrogen (Coal Gasification & Water-Gas Shift)

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Questions and Solutions

Question 9.1

Justify the position of hydrogen in the periodic table on the basis of its electronic configuration.
Solution:

Hydrogen, with the electronic configuration 1s^1, holds a unique position in the periodic table. Its single valence electron allows it to exhibit characteristics similar to both alkali metals (Group 1) and halogens (Group 17), leading to a dual behaviour.

Resemblance with Alkali Metals (Group 1):

  1. Like alkali metals, hydrogen has one electron in its outermost shell (1s^1). It can lose this electron to form a unipositive ion, H^+, similar to Li^+ ([He] 2s⁰) or Na^+ ([Ne] 3s⁰). For example: 2H \rightarrow 2H^+ + 2e^-.
  2. Hydrogen combines with electronegative elements to form compounds analogous to those formed by alkali metals. For instance, it forms oxides (like H_2O, similar to Na_2O), halides (like HCl, similar to NaCl), and sulphides (like H_2S, similar to Na_2S).

Resemblance with Halogens (Group 17):

  1. Both hydrogen and halogens need one electron to achieve a stable noble gas configuration. Hydrogen requires one electron to become like Helium (1s^2), while halogens require one electron to complete their octet (e.g., Fluorine 1s^2 2s^2 2p^5 needs one electron to become 1s^2 2s^2 2p^6). Consequently, hydrogen can gain one electron to form a uninegative ion, H^- (hydride ion), similar to halide ions like F^- or Cl^-. For example: H_2 + 2e^- \rightarrow 2H^-.
  2. Hydrogen forms diatomic molecules (H_2) and shares electrons to form covalent compounds with non-metals, much like halogens do (e.g., HCl, HBr).

Differences and Unique Position:

Despite these similarities, hydrogen differs significantly. It lacks metallic characteristics, has a much higher ionization enthalpy compared to alkali metals, and is less reactive than halogens. Furthermore, the H^+ ion is extremely small and cannot exist freely; it is always associated with other molecules. Due to this unique combination of properties and its inability to be definitively placed with either group, hydrogen is often placed separately at the top of the periodic table.

Question 9.2

Write the names of isotopes of hydrogen. What is the mass ratio of these isotopes?
Solution:

Hydrogen has three naturally occurring isotopes, distinguished by the number of neutrons in their nucleus:

  1. Protium (^1H): This is the most common isotope, consisting of one proton and one electron. Its nucleus has no neutrons.
  2. Deuterium (^2H or D): This isotope consists of one proton and one neutron in its nucleus, along with one electron.
  3. Tritium (^3H or T): This isotope consists of one proton and two neutrons in its nucleus, along with one electron. Tritium is radioactive.

The mass of these isotopes is primarily determined by the number of protons and neutrons. Since Protium has a mass number of 1, Deuterium has a mass number of 2, and Tritium has a mass number of 3, their mass ratio is:

Mass Ratio of Protium : Deuterium : Tritium = 1 : 2 : 3

Question 9.3

Why does hydrogen occur in a diatomic form rather than in a monoatomic form under normal conditions?
Solution:

Under normal conditions, hydrogen exists predominantly as a diatomic molecule (H_2) rather than as individual atoms (H) primarily due to its high ionization enthalpy and the stability gained by forming a covalent bond.

The ionization enthalpy of a hydrogen atom is very high (1312 \text{ kJ mol}^{-1}). This means a significant amount of energy is required to remove its single electron to form a H^+ ion. Consequently, hydrogen atoms do not readily exist in the monoatomic form as H^+ ions.

Instead, two hydrogen atoms can achieve a more stable state by sharing their electrons to form a strong covalent bond. Each hydrogen atom contributes its single electron to form a shared pair, resulting in the H_2 molecule where each atom effectively achieves the stable electronic configuration of Helium (1s^2).

Therefore, the formation of the stable H-H covalent bond makes the diatomic form (H_2) energetically more favorable than the monoatomic form under normal conditions.

Question 9.4

How can the production of dihydrogen, obtained from 'coal gasification', be increased?
Solution:

Coal gasification is a process where coal reacts with steam at high temperatures to produce a mixture of gases known as water gas, which contains carbon monoxide (CO) and dihydrogen (H_2). The primary reaction is:

C_{(s)} + H_2O_{(g)} \xrightarrow{1270 \text{ K}} CO_{(g)} + H_{2(g)}

(Coal) (Steam) (Carbon Monoxide) (Dihydrogen)

To increase the yield of dihydrogen (H_2) from this process, the carbon monoxide (CO) produced can be further reacted with more steam. This is achieved through the water-gas shift reaction. This reaction is typically carried out in the presence of a catalyst, such as iron chromate, at elevated temperatures.

The water-gas shift reaction is represented as:

CO_{(g)} + H_2O_{(g)} \xrightarrow{\text{Catalyst, Heat}} CO_2_{(g)} + H_{2(g)}

(Carbon Monoxide) (Steam) (Carbon Dioxide) (Dihydrogen)

In this reaction, the carbon monoxide reacts with steam to produce additional dihydrogen and carbon dioxide. By effectively converting the CO into more H_2, the overall production of dihydrogen from the initial coal gasification process is significantly increased.

Common mistakes

  • Confusing hydrogen's resemblance to alkali metals and halogens without noting its differences.
  • Incorrectly stating the mass ratio of hydrogen isotopes.
  • Not fully explaining the high ionization enthalpy's role in hydrogen's diatomic nature.
  • Overlooking the water-gas shift reaction as a method to increase dihydrogen yield.

Revision tips

  • Focus on the dual nature of hydrogen and its justification for its periodic table placement.
  • Memorize the names and mass ratios of hydrogen's isotopes.
  • Understand the energy considerations (ionization enthalpy) behind H₂ formation.
  • Review the chemical equations for coal gasification and the water-gas shift reaction.

Practice MCQs

Q1. What is the electronic configuration of hydrogen?

Q2. Which of the following is NOT an isotope of hydrogen?

Q3. What is the approximate mass ratio of Protium: Deuterium: Tritium?

Q4. Why does hydrogen prefer to exist as H₂ rather than H?

Q5. The water-gas shift reaction is used to increase the yield of dihydrogen from:

Frequently asked questions

Why is hydrogen's position in the periodic table unique?

Hydrogen's position is unique because its electronic configuration (1s¹) allows it to resemble both alkali metals (by losing an electron) and halogens (by gaining an electron), but it doesn't perfectly fit into either group.

What are the three isotopes of hydrogen?

The three isotopes of hydrogen are Protium (¹H), Deuterium (²H or D), and Tritium (³H or T).

What is the mass ratio of hydrogen isotopes?

The mass ratio of Protium, Deuterium, and Tritium is approximately 1:2:3.

Why does hydrogen exist as H₂ and not as H?

Hydrogen has a high ionization enthalpy, making it energetically favorable to form a stable covalent bond with another hydrogen atom, resulting in the diatomic molecule H₂.

How can the production of dihydrogen from coal gasification be increased?

The yield of dihydrogen from coal gasification can be increased by using the water-gas shift reaction, where the carbon monoxide produced is reacted with steam in the presence of a catalyst.

What is the significance of Deuterium (D)?

Deuterium is a heavier isotope of hydrogen used in nuclear reactions and as a tracer in chemical and biological studies. Its oxide, heavy water (D₂O), has unique properties.

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