CBSE Class 12 Chemistry 2022 Term-2 Previous Year Question Paper (Set-3)
This is the CBSE Class 12 Chemistry (Theory) Term-II Previous Year Question Paper from 2022, Set-3. With a total of 35 marks and a duration of 2 hours, this board question paper is divided into three sections: Section A, Section B, and Section C. Section A contains three very short-answer type questions, each worth 2 marks. Section B comprises eight short-answer type questions, each carrying 3 marks. Section C features one case-based question worth 5 marks. Solving this previous year's question paper is crucial for students to understand the exam pattern, identify important topics, and enhance their preparation for the upcoming board examinations.
Quick info
| Board | CBSE |
|---|---|
| Class | 12 |
| Subject | Chemistry |
| Session | 2022 |
| Language | English |
| Type | Previous Year Question Paper |
| Exam type | Board Exam |
Paper pattern
The question paper contains 12 questions divided into three sections: Section A (3 VSA questions, 2 marks each), Section B (8 SA questions, 3 marks each), and Section C (1 case-based question, 5 marks). Total marks: 35, Time: 2 hours.
Topics covered
Paper topics
- Chemical Kinetics
- Aldehydes and Ketones
- Carboxylic Acids and Derivatives
Important topics
- Wolff-Kishner reduction
- Cannizzaro reaction
- Acid strength comparison
- Boiling point comparison
- Order of reaction
- Integrated rate equation
PDF preview
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Question paper text
Date: 07/05/2022
SET No. 3
Question Paper Code
56/5/3
Time: 2 hrs.
Class-XII
Max. Marks: 35
CHEMISTRY (Theory)
Term-II
(CBSE-2022)
GENERAL INSTRUCTIONS
Read the following instructions very carefully and strictly follow them:
- This question paper contains 12 questions. All questions are compulsory.
- This question paper comprises of three sections - Section A, B and C.
- Section A - Q. No. 1 to 3 are very short-answer type questions carrying 2 marks each.
- Section B - Q. No. 4 to 11 are short-answer type questions carrying 3 marks each.
- Section C - Q. No. 12 is case based question carrying 5 marks.
- Use of log tables and calculators is not allowed.
SECTION-A
- Explain the following reactions:
<math>[1 \times 2 = 2]</math>
- Wolff-Kishner reduction
- Cannizzaro reaction
Sol. (a) Wolff-Kishner reduction:
[1] The carbonyl group of aldehydes or ketones are reduced to CH<sub>2</sub> group on treatment with hydrazine followed by heating with sodium or potassium hydroxide in high boiling solvent such as ethylene glycol.
<math>C = O \xrightarrow{NH_2NH_2} C = NNH_2 \xrightarrow{KOH/ethylene glycol} CH_2 + N_2</math>
- Cannizzaro reaction: [1]
Aldehydes which do not have an <math>\alpha</math>-hydrogen atom, undergo self reduction and oxidation (disproportionation) reaction on heating with concentrated alkali. In this reaction, one molecule of the aldehyde is reduced to alcohol and another is oxidised to carboxylic acid salt.
<math display="block">H \supset C = O + H \supset C = O \xrightarrow{Conc. KOH} H - C - O K^{+} + CH_{3}OH</math>
Formaldehyde Potassium formate Methanol
<math>[1 \times 2 = 2]</math>
- Arrange the following in the increasing order of the property mentioned:
- CH<sub>3</sub>COOH, CICH<sub>2</sub>COOH, FCH<sub>2</sub>COOH (Acid strength)
- CH<sub>3</sub>CHO, CH<sub>3</sub>CH<sub>2</sub>OH, CH<sub>3</sub>CH<sub>2</sub>CH<sub>3</sub> (Boiling Points)
Sol. (a) Electron withdrawing group increases the acidic strength as it stabilizes the conjugate base. [1]
Order of acidic strength: CH<sub>3</sub>COOH < CICH<sub>2</sub>COOH < FCH<sub>2</sub>COOH
- Stronger the intermolecular forces of attraction, higher will be the boiling point. [1] Order of boiling point: CH<sub>3</sub>CH<sub>2</sub>CH<sub>3</sub> < CH<sub>3</sub>CHO < CH<sub>3</sub>CH<sub>2</sub>OH
<math>[1 \times 2 = 2]</math>
- Answer the following questions (Do any two):
- Identify the order of reaction from the following unit for its rate constant: Lmol-1s-1
- The conversion of molecules A to B follow second order kinetics. If concentration of A is increased to three times, how will it affect the rate of formation of B?
- Write the expression of integrated rate equation for zero order reaction
Sol. (a) Unit of rate constant for any nth order reaction could be written as following Unit = <math>(\text{mol } L^{-1})^{1-n} s^{-1}</math> <math>[\frac{1}{2}]</math>
Comparing this with given unit <math>L \text{ mol}^{-1} \text{ s}^{-1} = (\text{mol } L^{-1})^{1-n} \text{ s}^{-1}</math> <math>\Rightarrow</math> <math>(\text{mol } L^{-1})^{-1} \text{ s}^{-1} = (\text{mol } L^{-1})^{1-n} \text{ s}^{-1}</math>
<math>1 - n = -1</math>
n = 2
<math>[\frac{1}{2}]</math>
Frequently asked questions
What is this document?
This is the CBSE Class 12 Chemistry Term-2 Previous Year Question Paper from 2022, Set-3.
What is the total mark and time duration for this paper?
The total marks for this paper are 35, and the time duration is 2 hours.
How is the Chemistry paper structured?
The paper has three sections: Section A with very short-answer questions, Section B with short-answer questions, and Section C with a case-based question.
Why is solving previous year papers important for CBSE Class 12 Chemistry?
Solving previous year question papers helps students understand the board pattern, identify important topics, and improve their exam scores.
What types of questions are included in this paper?
The paper includes very short-answer, short-answer, and case-based questions covering topics like chemical reactions, acid strength, boiling points, and chemical kinetics.
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