CBSE Class 10 Mathematics Chapter 6: Triangles Notes

These notes for CBSE Class 10 Mathematics Chapter 6, Triangles, cover essential concepts for revision. The chapter introduces similar triangles, defining them by equal corresponding angles and proportional corresponding sides. It details the Basic Proportionality Theorem (Thales Theorem) and its converse. Key criteria for triangle similarity are explained: AA/AAA, SAS, and SSS. The notes also discuss the areas of similar triangles and the fundamental Pythagoras theorem along with its converse. Several practice problems and proofs are included, such as finding the radius of an inscribed circle in a right-angled triangle, proving relationships between sides and medians, and calculating distances. These notes provide a comprehensive overview for students preparing for their exams.

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Types of Triangles Timilar Tongruent Properties Different Angles

1. Similar Triangles:- Two triangles are said to be similar, if

(a) their corresponding angles are equal and (b) their corresponding sides are in proportion (or are in the same ration).

2. Basic proportionality Theorem [ or Thales theorem ].

3. Converse of Basic proportionality Theorem.

4. Criteria for similarity of Triangles.

(a) AA or AAA similarity criterion.

(b) SAS similarity criterion.

(c) SSS similarity criterion.

5. Areas of similar triangles.

6. Pythagoras theorem.

7. Converse of Pythagoras theorem

1. ABC is a right-angled triangle, right-angled at A. A circle is inscribed in it. The

lengths of the two sides containing the right angle are 6cm and 8 cm. Find the

radius of the in circle.

(Ans: r=2)

2. ABC is a triangle. PQ is the line segment intersecting AB in P and AC in Q such

that PQ parallel to BC and divides triangle ABC into two parts equal in area. Find

BP: AB.

Ans: Refer example problem of text book.

3. In a right triangle ABC, right angled at C, P and Q are points of the sides CA and

CB respectively, which divide these sides in the ratio 2: 1.

Prove that

9AQ2= 9AC2 +4BC2

9BP2= 9BC2 + 4AC2

9 (AQ2+BP2) = 13AB2

4. P and Q are the mid points on the sides CA and CB respectively of triangle ABC

right angled at C. Prove that 4(AQ2 +BP2) = 5AB2

Self Practice

5. In an equilateral triangle ABC, the side BC is trisected at D. Prove that 9AD2 = 7AB2

Self Practice

6. There is a staircase as shown in figure connecting points A and B. Measurements

of steps are marked in the figure. Find the straight distance between A and B.

(Ans:10)

Ans: Apply Pythagoras theorem for each right triangle add to get length of AB.

7. Find the length of the second diagonal of a rhombus, whose side is 5cm and one of

the diagonals is

6cm. (Ans: 8cm)

Ans: Length of the other diagonal

= 2(BO)

where BO = 4cm

8. Prove that three times the sum of the squares of the sides of a triangle is equal to

four times the sum of the squares of the medians of the triangle.

Ans: To prove 3(AB2 + BC2 + CA2) = 4 (AD2+ BE2 + CF2)

In any triangle sum of squares of any two sides is equal to twice the square of half

of third side, together with twice the square of medianbisecting it . 9. ABC is an isosceles triangle is which AB=AC=10cm.BC=12. PQRS is a rectangle inside the isosceles triangle. Given PQ=SR= y cm, PS=QR=2x. Prove

11. If ABC is an acute angled triangle , acute angled at B and prove that AC2 =AB2 + BC2 ?2BC × BD

Ans: Proceed as sum no. 10.

12. Prove that in any triangle the sum of the squares of any two sides is equal to twice the

square of half of the third side together with twice the square of the median, which

bisects the third side.

13. If A be the area of a right triangle and b one of the sides containing the right

angle, prove that the length of the altitude on the hypotenuse is

16. In the given figure, and E is the mid-point of CA. Prove that

17. ABCD is a parallelogram in the given figure, AB is divided at P and CD and Q so

that AP:PB=3:2 and CQ:QD=4:1. If PQ meets AC at R, prove that AR

18. Prove that the area of a rhombus on the hypotenuse of a right-angled triangle, with

one of the angles as 60o, is equal to the sum of the areas of rhombuses with one of

their angles as 60o drawn on the other two sides.

19. An aeroplane leaves an airport and flies due north at a speed of 1000 km/h. At the

same time, another plane leaves the same airport and flies due west at a speed of 1200

km/h. How far apart will be the two planes after 1½ hours.

20. ABC is a right-angled isosceles triangle, right-angled at B. AP, the bisector of , intersects BC at P. Prove that

Frequently asked questions

What are similar triangles?

Two triangles are similar if their corresponding angles are equal and their corresponding sides are in the same proportion.

What is the Basic Proportionality Theorem?

The Basic Proportionality Theorem states that if a line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the same ratio.

What are the criteria for similarity of triangles?

The criteria for similarity of triangles are AA (or AAA) similarity, SAS similarity, and SSS similarity.

What is the Pythagoras Theorem?

In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

What does the converse of the Pythagoras Theorem state?

If in a triangle, the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.

How are the areas of similar triangles related?

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

Are practice problems included in these notes?

Yes, these notes include various practice problems and proofs related to triangles for self-practice and exam preparation.

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