Question 9:The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 500M. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3S cm−1. Chapter 3: Electrochemistry Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 500M. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 ? 10?3S cm?1. is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 3 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 3: Electrochemistry is very essencial for getting good marks in CBSE Board examinations
Question 9:The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 500M. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3S cm−1.
Answer:Given that ,
Conductivity of the cell , κ = 0.146 × 10−3 S cm−1
Resistance of the cell , R = 1500 Ω
Formula of cell constant
Cell constant = κ × R
Plug the values we get
= 0.146 × 10−3 × 1500
= 0.219 cm−1
Copyright @ ncerthelp.com A free educational website for CBSE, ICSE and UP board.
