Question 8:The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Calculate its molar conductivity. Chapter 3: Electrochemistry Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm?1. Calculate its molar conductivity. is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 3 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 3: Electrochemistry is very essencial for getting good marks in CBSE Board examinations
Question 8:The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm−1. Calculate its molar conductivity.
Answer:Given that ,
κ = 0.0248 S cm−1 and c = 0.20 M
Formula of molar conductivity,
Λm = ( k × 1000)/M
Λm =(0.0248 × 1000 )/0.2
Λm =124 S cm2 mol−1
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