Question 2:Given the standard electrode potentials, K+/K = −2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V Mg2+/Mg = −2.37 V, Cr3+/Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Chapter 3: Electrochemistry Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Given the standard electrode potentials, K+/K = ?2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V Mg2+/Mg = ?2.37 V, Cr3+/Cr = ? 0.74V Arrange these metals in their increasing order of reducing power. is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 3 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 3: Electrochemistry is very essencial for getting good marks in CBSE Board examinations
Question 2:Given the standard electrode potentials,
K+/K = −2.93V, Ag+/Ag = 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = −2.37 V, Cr3+/Cr = − 0.74V Arrange these metals in their increasing order of reducing power.
Answer:Reducing power of metals increase with decrease of reduction potential. Hence the increasing order of reducing power will
Ag < Hg < Cr < Mg < K
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