Question 21: Gold (atomic radius = 0.144 nm) crystallises in a face–centred unit cell. What is the length of a side of the cell? Chapter 1: the Solid State Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Gold (atomic radius = 0.144 nm) crystallises in a face–centred unit cell. What is the length of a side of the cell is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 1 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 1: the Solid State is very essencial for getting good marks in CBSE Board examinations
Question 21: Gold (atomic radius = 0.144 nm) crystallises in a face–centred unit cell. What is the length of a side of the cell?
Answer
Given that
Radius of atom R= 0.144 nm
For a face–centered unit cell
Edge a = 2√2 R
Plug the values we get
Edge a= 0.144 x 2 x 1,414 nm
Edge a= 0.407 nm
Solution:– The length of a side of the cell = 0.407 nm
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