Home UP BOARD Question Papers NCERT Solutions Sample Papers CBSE Notes NCERT Books CBSE Syllabus

Analysis Shows That Nickel Oxide Has the Formula Ni0.98o1.00. Wha Exercise Chapter 1 the Solid State Chemistry Class

Question 16 Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions? Chapter 1: the Solid State Chemistry Class 12 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions is solved by our expert teachers. You can get ncert solutions and notes for class 12 chapter 1 absolutely free. NCERT Solutions for class 12 Chemistry Chapter 1: the Solid State is very essencial for getting good marks in CBSE Board examinations

Question 16 Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions?

AnswerFormula is Ni0.98O1.00
So the ration of Ni : O = 98:100
So if there are 100 atoms of oxygen then 98 atoms of Ni
Let number of atoms of Ni+2 = x
Then number of atoms of Ni+3 = 98–x
Charge on Ni = charge on O
So that oxygen has charge –2
3(98–x) + 2x = 2 (100)
294 –3x +2x = 200
–x = – 94
x = 94
Percentage of Ni+2        = (atom of Ni+2/total number of atoms of Ni)100
                                 =100(94/98)*100
                                  = 96%
Percentage of Ni+3             
                                  =100 – Ni+2
                                  =100 – 96
                                  = 4 %

Important Links

NCERT CBSE Notes Class 6 - 12 Download pdf

Ncert Solution for class 6 to 12 download in pdf

CBSE Model test papars Download in pdf

NCERT Books for Class 1- 12 Hindi & English Medium

Mathematics Biology Psychology
Chemistry English Economics
Sociology Hindi Business Studies
Geography Science Political Science
Statistics Physics Accountancy

CBSE Syllabus Class 9 to 12 Year 2021-22

Last year CBSE Question paper

Important Links

Follow Us On

Face book page ncerthelp twitter page youtube page linkdin page

Solved Last Year Question Paper

If You have any problem/query related to above page please send us your Query to ncerthelp@gmail.com with code Serial No465/40. Thanks

Please Share this webpage on facebook, whatsapp, linkdin and twitter.

Facebook Twitter whatsapp Linkdin

Copyright @ ncerthelp.com A free educational website for CBSE, ICSE and UP board.