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Question 2. The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

Question 1. The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

Solution: Let cost of one bat  = Rs x
Cost of one ball      = Rs y
3 bats and 6 balls for Rs 3900 So that
3 x + 6y = 3900                     … (1)
Divide complete equation by 3 we get
X+ 2y = 1300                       
Subtract 2y both side we get
X         = 1300 – 2y  

Plug y = - 1300, 0 and 1300  we get
X = 1300 – 2 ( - 1300 )         = 1300 + 2600           =  3900
X= 1300 -2(0)                        = 1300 -0                   = 1300
X= 1300 – 2(1300)               = 1300 – 2600           = - 1300  

X

3900

1300

-1300

y

-1300

0

1300

Given that  she buys another bat and 2 more balls of the same kind for Rs 1300
So we get
x  + 2 y = 1300                      … (2)
Subtract 2y both side we get
X         = 1300 – 2y
Plug y = - 1300, 0 and 1300  we get
X         = 1300 – 2 ( - 1300 )             = 1300  +  2600         =  3900
X         = 1300 – 2 ( 0 )                      = 1300 - 0                  = 1300
X         = 1300 – 2(1300)                  = 1300 – 2600           = -1300

X

3900

1300

-1300

y

-1300

0

1300

Algebraic representation
3 x + 6 y = 3900                    … (1)
x + 2 y    = 1300                     … (2)

The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys





Question 2. The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she bu


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