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Question 3. Obtain all other zeroes of 3x4 + 6x3 – 2x2 – 10x – 5, if two of its zeroes are √(5/3) and - √(5/3)

Question 3. Obtain all other zeroes of 3x4 + 6x3 – 2x2 – 10x – 5, if two of its zeroes are √(5/3) and  - √(5/3)

Quotient is x² + 2x + 1 = 0
Compare the equation with    ax²  + bx  + c  = 0
We get
a = 1 ,b = 2, c = 1
To factorize the value we have to find two value which

sum is equal to b         = 2
product is        a x c     = 1 x 1 = 1
1 and 1 are such number which
sum is            1 + 1    = 2
product is  1 x 1          = 1
So we can write middle term  2x  = x  + x 
We get
x² + x + x + 1 = 0
x (x +1) +1(x +1) = 0
( x + 1)( x + 1) = 0
x +1 = 0, x + 1= 0
x = -1 , x = - 1
so our zeroes are     - 1  -1 , √(5/3) and  - √(5/3)



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Question 3. Obtain all other zeroes of 3x4 + 6x3 – 2x2 – 10x – 5, if two of its zeroes are

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