**1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.**

**(ii) 4s² – 4s + 1**

Factorize the equation

Compare the equation with as² + bs + c = 0

We get

a = 4 , b = -4, c = 1

To factorize the value we have to find two value which

sum is equal to b = -4

product is a x c = 4

-2 and -2 are such number which

sum is (– 2)+( – 2) = - 4

product is (- 2 )* (- 2) = 4

So we can write middle term - 4s = -2s – 2s

We get

4s² - 2s - 2s + 1 = 0

2s(2s -1) -1(2s -1) = 0

(2s - 1) (2s - 1) = 0

Solve for first zero

2s - 1 =0

2s = 1

s = ½

Solve for second zero

2s - 1 =0

2s = 1

S = ½

sum of zeros ½ + ½ = 2/2 = 1

product of zeros ½ x ½ = 1/4

Sum of zero = -b/a = -(-4/4) = 1

Product of zero= c/a = 1/4 = 1/4