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## Question 2. Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 (ii) 510 and 92 (iii) 336 and 54

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Question 2. Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.
26 and 91 (ii) 510 and 92 (iii) 336 and 54

(i)

26        = 2 x 13
91        =7 x 13
HCF    = 13
LCM    =2 x 7 x 13     =182
Product of two value           26 x 91           = 2366
Product of HCF and LCM   13 x 182         = 2366
Hence, product of two numbers = product of HCF × LCM

(ii)

510     = 2 x 3 x 5 x 17
92        =2 x 2 x 23
HCF    =2
LCM    =2 x 2 x3 x 5 x 17 x 23         = 23460
Product of both values        510x92           = 46920
Product of HCF and LCM   2x23460         =46920
Hence, product of two numbers = product of HCF × LCM

(iii)

336     = 2 x 2 x 2 x 2 x 3 x 7
54        = 2 x 3 x 3 x 3
HCF    = 2 x 3                                                = 6
LCM    = 2 x 2 x 2 x 2 x 3 x 3 x 3 x 7           =3024
Product of number               336 x 54         =18144
Product of HCF and LCM   6 x 3024         = 18144
Hence, product of two numbers = product of HCF × LCM

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NCERT Solutions Class 10 Chapter 1 Questions 2 Find LCM and HCF of following pairs of integers, verify LCM × HCF = product of two numbers
how to find lCM and HCF using prime factorization method, Find LCM HCF verify LCM × HCF = product of two numbers