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Question 4. Use Euclid’s division lemma to show that the square of any positive integer is either of the form 3m or 3m + 1 for some integer m

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4. Use Euclid’s division lemma to show that the square of any positive integer is either of the form 3m or 3m + 1 for some integer m.

Answer:

Let take a as any positive integer and b = 3.
Then using Euclid’s algorithm we get a = 3q + r  here r is remainder and value of q is more than or equal to 0  and r = 0, 1, 2 because 0 < r < b  and the value of b is 3 So our possible values will 3q+0 , 3q+1 and 3q+2

Now find the square of values 
Use the formula (a+b)² = a² + 2ab +b² to open the square bracket 
(3q)²             = 9q²   if we divide by 3 we get no remainder  

we can write it as 3*(3q²)  so it is in form of 3m  here m = 3q²
(3q+1)²         = (3q)² + 2*3q*1  + 1²       
=9q² + 6q +1 now divide by 3 we get 1 remainder

so we can write it as 3(3q² + 2q) +1 so we can write it in form of 3m+1 and value of m is 3q² + 2q  here
(3q+2)²         = (3q)² + 2*3q*2  + 2² 
=9q² + 12q +4  now divide by 3 we get 1 remainder

so we can write it as 3(3q² + 4q +1) +1 so we can write it in form of 3m +1 and value of m will 3q² + 4q +1
Square of any positive integer is either of the form 3m or 3m + 1 for some integer m.




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Class 10 maths solutions Use Euclid’s division lemma to show that the square of any positive integer is either of the form 3m or 3m + 1
Use Euclid’s division lemma to show that the square of any


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